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olganol [36]
3 years ago
6

I REALLY NEED HELP!!!!

Mathematics
2 answers:
Anna35 [415]3 years ago
8 0
Divide x^4+x^3+7x^2-6x+8 by x+2+2x+8 using long polynomial division.

Answer:
x^2-x+1
dangina [55]3 years ago
4 0

Answer:

x²-x+1

Step-by-step explanation:

We write the dividend, x⁴+x³+7x²-6x+8, under the division box.  We write the divisor, x²+2x+8, outside the box to the left.

We see how many times x² goes into x⁴.  It will go x² times.  We write this on the line above the dividend.  We multiply back through;

x²(x²+2x+8) = x⁴+2x³+8x²

We write this under the first three terms of the dividend.  We then subtract:

(x⁴+x³+7x²)-(x⁴+2x³+8x²) = -1x³-1x²

This goes below the subtraction.  We bring down the next term, -6x.

Next we see how many times x² goes into -1x³.  It goes -x times; we write this beside the x² in the quotient.  We multiply back through:

-x(x²+2x+8) = -x³-2x²-8x

This goes below the -1x³-1x²-6x.  We subtract the two:

(-1x³-1x²-6x)-(-x³-2x²-8x) = -1x³+1x³-1x²+2x²-6x+8x = 1x²+2x

We write this below the last line in the work.  We bring down the last term, 8.

Now we see how many times x² goes into 1x².  It goes 1 time; since this is positive, we write +1 beside the answer we have at the top.  Multiply back through:

1(x²+2x+8) = x²+2x+8

Now we subtract:

(x²+2x+8)-(x²+2x+8) = 0

This makes our answer x²-x+1

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Please help me withe this proof as well.​
baherus [9]

- D is the midpoint of AB, E is the midpoint of BC

Answer: A. Given

I left off DB||FC because that's not given.  But we can construct it.

Construct line through C parallel to AB.  Extend DE to intersect and call the meet F.

- DB || FC

By Construction

----

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Corresponding parts ...

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Step-by-step explanation:

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valentina_108 [34]
If you want to solve for x, then
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