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inysia [295]
3 years ago
10

Select the Correct Answer Consider the following Equation 12w - 27 = -34 + 14 Which Equation has the same solution as the equati

on given above?A. -2w + 21 = -8w + 36\\B. -\frac{5}{6} w + 2 = -34 + 14w\\C. -47 - 10w = -9w -40 - 3w\\D. \frac{9}{7} w = \frac{13}{14} w + 2
Mathematics
1 answer:
cricket20 [7]3 years ago
6 0
12w - 27 = -34 + 14
w = 7/12

A -2w+21=-8w+36
w=17/8

B -5/6 w + 2 = -34+14w
w=216/89

C -47-10w=-9w-40-3w
w= 7/2

D 8/7w=13/14w+2
w=28/5


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The antibiotic clarithromycin is eliminated from the body according to the formula A(t) = 500e−0.1386t, where A is the amount re
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Answer:

Time(t) = 11.61 hours (Rounded to two decimal place)

Step-by-step explanation:

Given: The antibiotic  clarithromycin is eliminated from the body according to the formula:

A(t) = 500e^{-0.1386t}                 ......[1]

where;

A - Amount remaining in the body(in milligram)

t - time in hours after the drug reaches peak concentration.

Given: Amount of drug in the body is reduced to 100 milligrams.

then,

Substitute the value of A = 100 milligrams in [1] we get;

100= 500e^{-0.1386t}

Divide both sides by 500 we get;

\frac{100}{500}=\frac{ 500e^{-0.1386t}}{500}

Simplify:

\frac{1}{5} = e^{-0.1386t}

Taking logarithm both sides with base e, then we have;

\log_e (\frac{1}{5})= \log_e (e^{-0.1386t})

\log_e (\frac{1}{5})=-0.1386t         [ Using \log_e e^a =a ]

or

\log_e (0.2)=-0.1386t

-1.6094379124341 = -0.1386t

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then;

t = \frac{-1.6094379124341}{-0.1386}

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t ≈11.61 hours.

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Answer:

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Step-by-step explanation:

1. Let's review the data given to us for solving the question:

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2. Let's find the future value of this investment after 4 years, using the following formula:

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Answer:

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