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3 years ago

Which point is on the line y=-2+3? (-2,-1) (3,3) (3,-3) (-3,-9)

Mathematics

1 answer:

puteri [66]3 years ago

8 0

Answer:

The point (3, -3) is on the line.

Step-by-step explanation:

In order to find if it is a solution, input the numbers into the appropriate places in the equation.

y = -2x + 3

-3 = -2(3) + 3

-3 = -6 + 3

-3 = -3

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SVETLANKA909090 [29]

$\huge \boxed{\mathbb{QUESTION} \downarrow}$

$\begin{bmatrix} \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \end{bmatrix} \begin{bmatrix} \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { - 1 } & { 1 } & { 5 } \end{array} \end{bmatrix}$

$\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}$

In matrix multiplication, the number of columns in the 1st matrix is equal to the number of rows in the 2nd matrix.

$\left(\begin{matrix}2&3\\5&4\end{matrix}\right)\left(\begin{matrix}2&0&3\\-1&1&5\end{matrix}\right)$

Multiply each element of the 1st row of the 1st matrix by the corresponding element of the 1st column of the 2nd matrix. Then add these products to obtain the element in the 1st row, 1st column of the product matrix.

$\left(\begin{matrix}2\times 2+3\left(-1\right)&&\\&&\end{matrix}\right)$

The remaining elements of the product matrix are found in the same way.

$\left(\begin{matrix}2\times 2+3\left(-1\right)&3&2\times 3+3\times 5\\5\times 2+4\left(-1\right)&4&5\times 3+4\times 5\end{matrix}\right)$

Simplify each element by multiplying the individual terms.

$\left(\begin{matrix}4-3&3&6+15\\10-4&4&15+20\end{matrix}\right)$

Now, sum each element of the matrix.

$\large\boxed{\boxed{\left(\begin{matrix}1&3&21\\6&4&35\end{matrix}\right) }}$

7 0

2 years ago

Which of the following is the solution to |-2x-15|≤7

sergeinik [125]

Answer:

Step-by-step explanation:

C. -11<x<-4

|-2x-15|<7 split into possible cases

- 2x - 15 < 7, - 2 x - 15 > 0

-(- 2x - 15 ) <7, -2x - 15 < 0 solve the inequalities

x>-11, x < -15/2

x< -4, x> -15/2 Find the intersections

[ -11, -15/2 ]

-15/2, -4] Find the union

[-11, -4 ] Simplify

-11<x<-4

5 0

3 years ago

Please help me if you can. Please also write how you got the answer thank you.

babunello [35]

Answer:

Question 9: Variables: (smallest) s, q, r (largest)

Question 10: 5 whole numbers (7, 8, 9, 10, and 11)

Step-by-step explanation:

For question nine, there are two given statements... s=q-2 and q<r. Say we plug in 10000 (a really big #) in for q, then we would get s=9998 and r>10000. This way, we can see that s would be the smallest, then q, and r is the largest. <em>(q<r can be written as r>q)</em>

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For question 10, it states $\frac{1}{4}$ . This can be split into $\frac{3}{x}$ and $\frac{3}{x}$ . When x is 12 in the first equation then $\frac{3}{12} = \frac{1}{4}$ and when x is 6 in the second equation $\frac{3}{6} =0.5$ (0.5 is also $\frac{1}{2}$ ). Therefore, x must be a whole number less than 12 and greater than 6, and it cannot be either 12 or 6. Whole numbers between 6 and 12 are 7, 8, 9, 10, and 11 or 5 whole numbers.

4 0

3 years ago

Which function represents g(x), a reflection of f(x) = 6across the y-axis?

Otrada [13]

Answer: D.) $g(x) = 6(3)^{-x}$

Step-by-step explanation: We are given an exponential function f(x).

g(x) is an exponential function that is being reflected across y-axis.

According to rules of transformations y=f(-x).

That is variable x is being multiplied by a negative sign.

In the given options $g(x) = 6(3)^{-x}$ , the variable x is being multiplied by a negative sign.

Therefore, correct option is D option.

4 0

3 years ago

Read 2 more answers

Can you help me with my math questions

GrogVix [38]

$p^2+2(7)p+7^2=(p+7)^2$

Justification:

Given: $p^2+14p+49$

Split the middle term;

$=p^2+7p+7p+49$

Factor:

$=p(p+7)+7(p+7)$

$=(p+7)(p+7)$

$=(p+7)^2$

QUESTION 3a

The given expression for the area of the rectangle is $36x^2-12x+1$ .

This is equal to the indicated area which is $289\;in^2$

This implies that

$36x^2-12x+1=289$

$\Rightarrow (6x-1)^2=289$

$\Rightarrow (6x-1)(6x-1)=289$

$\Rightarrow l=(6x-1),w=(6x-1)$

This implies that, the dimensions of the rectangle are equal;

Using the square root method, we obtain

$\Rightarrow (6x-1)=\pm \sqrt{289}$

$\Rightarrow (6x-1)=\pm 17$

$\Rightarrow 6x=1\pm 17$

$\Rightarrow 6x=18 \:or\:6x=-16$

$\Rightarrow x=3 \:or\:x=-\frac{2}{3}$

We discard the negative value.

The side length of this rectangle is

$\Rightarrow l=(6(3)-1)=17,w=6(3)-1=17$

QUESTION 3b

The given expression for the area of the rectangle is $25x^2-50x+25$ .

This is equal to the indicated area which is $1225\;in^2$

This implies that

$25x^2-50x+25=1225$

$25(x^2-2x+1)=1225$

$(5(x-1))^2=35^2$

$5(x-1)5(x-1)=49$

$\Rightarrow l=5(x-1),w=5(x-1)$

This implies that, the dimensions of the rectangle are equal;

Using the square root method, we obtain

$\Rightarrow 5(x-1)=\pm \sqrt{1225}$

$\Rightarrow 5(x-1)=\pm 35$

$\Rightarrow x=1\pm 7$

$\Rightarrow x=8 \:or\:x=-6$

We discard the negative value.

The side length of this rectangle is

$\Rightarrow l=5(8-1)=35,w=5(8-1)=35$

QUESTION 3c

The given expression for the area of the rectangle is $49x^2-56x+16$ .

This is equal to the indicated area which is $289\;in^2$

This implies that

$49x^2-56x+16=289$

$(7x-4)^2=289$

$(7x-4)(7x-4)=289$

$\Rightarrow l=(7x-4),w=(7x-4)$

Applying the laws of indices gives;

$(7x-4)^2=17^2$

This implies that;

$7x-4=17$

$7x=21$

$x=3in.$

The side length of this rectangle is

$\Rightarrow l=7(3)-4=17\:in.,w=7(3)-4=17\:in.$

Dont forget that the square is also a rectangle.

5 0

3 years ago

Read 2 more answers