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Zepler [3.9K]
3 years ago
5

What is the rate of change of equation x=9

Mathematics
1 answer:
Delicious77 [7]3 years ago
5 0
Erm..

9 I guess..

Good luck?
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On the scale drawing of Cold Lake Camp, the mess hall is 5 cm from the lodge. The scale for the map is 2 cm = 100 m.
romanna [79]

Answer:

The answer is 250 meters from the lodge

6 0
3 years ago
(x^2 - x^(1/2))/(1-x^(1/2))
Levart [38]
\frac { \left( { x }^{ 2 }-{ x }^{ \frac { 1 }{ 2 }  } \right)  }{ \left( 1-{ x }^{ \frac { 1 }{ 2 }  } \right)  }

\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x }  \right)  }{ \left( 1-\sqrt { x }  \right)  } \cdot 1

\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x }  \right)  }{ \left( 1-\sqrt { x }  \right)  } \cdot \frac { \left( 1+\sqrt { x }  \right)  }{ \left( 1+\sqrt { x }  \right)  }

\\ \\ =\frac { { x }^{ 2 }+{ x }^{ 2 }\sqrt { x } -\sqrt { x } -x }{ 1+\sqrt { x } -\sqrt { x } -x }

\\ \\ =\frac { -\sqrt { x } \left( 1-{ x }^{ 2 } \right) -x\left( 1-x \right)  }{ \left( 1-x \right)  }

\\ \\ =\frac { -\sqrt { x } \left( 1+x \right) \left( 1-x \right) -x\left( 1-x \right)  }{ \left( 1-x \right)  }

\\ \\ =\frac { \left( 1-x \right) \left\{ -\sqrt { x } \left( 1+x \right) -x \right\}  }{ \left( 1-x \right)  }

\\ \\ =-\sqrt { x } \left( 1+x \right) -x\\ \\ =-{ x }^{ \frac { 1 }{ 2 }  }\left( 1+{ x }^{ \frac { 2 }{ 2 }  } \right) -x

\\ \\ =-{ x }^{ \frac { 1 }{ 2 }  }-{ x }^{ \frac { 3 }{ 2 }  }-x\\ \\ =-\sqrt { x } -\sqrt { { x }^{ 3 } } -x
3 0
3 years ago
Read 2 more answers
Calculate ten minus four point three five
Mrac [35]
the answer is five point six five, 5.65
8 0
3 years ago
In a 24 km race, during which each runner maintains a constant speed throughout, Alice crosses the finish line while Becky is st
mr_godi [17]

Answer:6km

Step-by-step explanation:

Given

when Alice finishes the race Becky is 8km From finishing line

and caitlin 12 km from finishing line.

Suppose t is the time require by Alice to finish the race

andV_a,V_b,V_c be the velocity of alice ,becky and caitlin

thus t=\frac{24}{V_a}=\frac{24-8}{V_b}=\frac{24-12}{V_c}

thus \frac{V_b}{V_c}=\frac{4}{3}

say t' is time required by beckey  to complete 8 km thus

V_b\times t'=8

therefore for Caitlin

V_c\times t'=\frac{8}{V_b}\times V_c=6

Thus caitlin will cover a distance of 6 km in t' time and 6 km away from finishing.

7 0
3 years ago
The diameter of circle p below is 39.4 what is the approximate area of circle p???
Rufina [12.5K]
A= π r2 
<span>r= 39.4/2=19.7
A= 19.7 x 19.7=388.09
A= pi x 388.09= </span>1218.6026<span>
A= 1218.6026

</span>
3 0
3 years ago
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