Since AS is a height issued from A and the perpendicular bisector of [MP] at the same time (given), so the triangle AMP is an isosceles triangle of vertex A. Then, AM=AP
MS=SP ( AS bisects MP as stated in the given )
AS is a common side between triangles ASM and ASP
Therefore, triangles ASM and ASP are congruent (SSS)
The answer for the problem is 27.75
Answer:
-9/14
Step-by-step explanation:
Answer:
4 / x¹⁴y⁸
Step-by-step explanation:
eliminate parenthese by multiplying all exponents inside parentheses by the exponent outside the parentheses:
1/2⁶ ÷ 1/4⁴ = 1/64 ÷ 1/256 which equals 256/64 or 4
x⁻⁶y⁴ ÷ x⁸y¹² = x⁻¹⁴y⁻⁸ = 1/x¹⁴ · 1/y⁸
put it all together to get:
4÷(x¹⁴y⁸)
