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Yuri [45]
3 years ago
8

A rectangular mat has a length of 12 in. and a width of 4 in. Drawn on the mat are three circles. Each circle has a radius of 2

in. Some friends play a game throwing darts onto the mat to see who can land a dart in one of the circles.
Assuming that a dart always lands on the mat, what is the probability that a dart thrown at random will land inside one of the circles?

Use 3.14 to estimate Pi.

Enter your answer, as a decimal rounded to the nearest hundredth, in the box.



P(landing in a circle) =

Mathematics
1 answer:
pickupchik [31]3 years ago
7 0

|\Omega|=4\cdot12=48\\ |A|=3\cdot3.14\cdot2^2=37.68\\\\ P(A)=\dfrac{37.68}{48}\approx0.79

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1,000,000,000 (one billion)

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Use the distributive property to express 30 + 75
OleMash [197]
Click on  the box for more details on how to <span>distributive property to express 30 + 75.</span>

8 0
3 years ago
Read 2 more answers
The two rectangles shown have equal areas. Find the value of x
Tema [17]

Answer:

x=18

Step-by-step explanation:

We need to find the areas of the rectangles

1st rectangle

A= l*w

A = (2x+4)*9

   = 18x+36



2nd rectangle

A = l*w

   = 15*(3x-30)

    = 45x-450


Since the area of the rectangles are equal, we set these two equations equal

18x+36 = 45x-450

Subtract 18x from each side

18x-18x+36 = 45x-18x-450

36 = 27x-450

Add 450 to each side

36+450 =27x

486 = 27x

Divide by 27 on each side

486/27 = 27x/27

18=x


7 0
3 years ago
For the equation ae^ct=d, solve for the variable t in terms of a,c, and d. Express your answer in terms of the natural logarithm
saveliy_v [14]

We have been given an equation ae^{ct}=d. We are asked to solve the equation for t.

First of all, we will divide both sides of equation by a.

\frac{ae^{ct}}{a}=\frac{d}{a}

e^{ct}=\frac{d}{a}

Now we will take natural log on both sides.

\text{ln}(e^{ct})=\text{ln}(\frac{d}{a})

Using natural log property \text{ln}(a^b)=b\cdot \text{ln}(a), we will get:

ct\cdot \text{ln}(e)=\text{ln}(\frac{d}{a})

We know that \text{ln}(e)=1, so we will get:

ct\cdot 1=\text{ln}(\frac{d}{a})

ct=\text{ln}(\frac{d}{a})

Now we will divide both sides by c as:

\frac{ct}{c}=\frac{\text{ln}(\frac{d}{a})}{c}

t=\frac{\text{ln}(\frac{d}{a})}{c}

Therefore, our solution would be t=\frac{\text{ln}(\frac{d}{a})}{c}.

5 0
3 years ago
Latoya, Milan, and Hong served a total of 154 orders Monday at the school cafeteria. Latoya served 10 more orders than Milan, Ho
Tems11 [23]

Orders served by Latoya, Milan and Hong are 34, 24, 96 respectively.

<u>Solution:</u>

Given, Latoya, Milan, and Hong served a total of 154 orders Monday at the school cafeteria.  

Let orders served by Latoya ne a, orders served by Milan be b and orders served by hong be c.

Then, a + b + c = 154 ⇒ (1)

Latoya served 10 more orders than Milan, ⇒ a = b + 10

Hong served 4 times as many orders as Milan. ⇒ c = 4b

We have to find how many orders did they each serve?

Now, substitute a and c values in (1)

(b + 10) + b + 4b = 154

b + b + 4b = 154 – 10

6b = 144

b = 24

Then, a = 24 + 10 = 34 and c = 4 x 24 = 96.

Hence, orders served by Latoya, Milan and Hong are 34, 24, 96 respectively.

5 0
3 years ago
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