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4 years ago

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What is the value of y in the equation 6.4x + 2.8y = 44.4, when x = 3?

2 answers:

kiruha [24]4 years ago

7 0

Answer: 9

Step-by-step explanation: plug 3 into the x, then use the order of operations/ pemdas to solve. first multiply 6.4 and 3 (=19.2) then subtract the answer from 44.4 (now the equation is 2.8y=25.2) then divide 2.8 from 25.2 to get x alone and you are left with x=9

Andrej [43]4 years ago

5 0

Answer:

y = 9

Step-by-step explanation:

So if x = 3, we can sub that into the equation.

This gives us:

6.4 (* 3) + 2.8y = 44.4

so:

19.2 + 2.8y = 44.4

25.2 = 2.8y

so

y = 9

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3 years ago

Solve For 1/4 + 1/2 + x = - 3/4

ivann1987 [24]

Answer:

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Step-by-step explanation:

Ok think about it 1/4 plus 1/2 is 3/4

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3 years ago

trasher [3.6K]

Answer:

See explanation

Step-by-step explanation:

The given complex number are:

$z_1=-3\sqrt{3}+3i$

and

$z_2=6\cos 150\degree+6i\sin 150\degree$

When we rewrite $z_1=-3\sqrt{3}+3i$ in complex form, we obtain;

$z_1=r(\cos \theta+i\sin \theta)$

where

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and

$\theta=tan^{-1}(\frac{y}{x})$

$\implies \theta=tan^{-1}(\frac{-3\sqrt{3}}{3})=150\degree$

Hence,

$z_1=6(\cos 150\degree+i\sin 150\degree)$

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3 years ago

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Dmitry [639]

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3 years ago

Read 2 more answers