Answer:
The standard deviation of the number of rushing yards for the running backs that season is 350.
Step-by-step explanation:
Consider the provided information.
The mean number of rushing yards for the running backs that season is 790 yards. One running back had 1,637 rushing yards for the season, which is 2.42 standard deviations above the mean number of rushing yards.
Here it is given that mean is 790 and 1637 is 2.42 standard deviations above the mean.
Use the formula:
Here z is 2.42 and μ is 790, substitute the respective values as shown.
Hence, the standard deviation of the number of rushing yards for the running backs that season is 350.
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Answer:
after 2 seconds
Step-by-step explanation:
We want to find t such that h = 0.
0 = -16t² +8t +48
0 = 2t² -t -6 . . . . . . . divide by -8
0 = (t -2)(2t +3) . . . . factor
The only positive solution is t = 2, which makes the first factor zero.
Stella will land in the water at t = 2 seconds.
Answer: here u go
Step-by-step explanation:
Answer:
<h2>mStep-by-step explanation:
From the question all the angles are on a a straight line which means the sum of their angles is 180 and one of the angles is 90°
So to find m 6 , add
m 5 and 90 and subtract the result from 180°
That's
m5 + m
6 + 90 = 180
m6 = 180 - 90 - m
5
m6 = 180 - 90 - 22
We have the final answer as
<h3>mHope this helps you