The given operation involves just swapping the two rows, so carrying out 
on the matrix gives
![\left[\begin{array}{cc|c}5&5&5\\1&-\dfrac23&5\end{array}\right]\to\left[\begin{array}{cc|c}1&-\dfrac23&5\\5&5&5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Cc%7D5%265%265%5C%5C1%26-%5Cdfrac23%265%5Cend%7Barray%7D%5Cright%5D%5Cto%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Cc%7D1%26-%5Cdfrac23%265%5C%5C5%265%265%5Cend%7Barray%7D%5Cright%5D)
Find the inverse of g(x) = 3x^2 - 5
1 answer:
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Answer:
29. 15.87%
30. 4.75%
31. 0.62%
32. probability cannot be calculated (0%)
Step-by-step explanation:
We have that the formula of the normal distribution is:
z = (x - m) / sd
where x is the value we are going to evaluate, m is the mean and sd is the standard deviation
x = 16 and m = 16.5
when sd = 0.5
z = (16 - 16.5) /0.5
z = -1
Now when looking in the z table, we have that the corresponding value is 0.1587, that is, the probability is 15.87%
when sd = 0.3
z = (16 - 16.5) /0.3
z = -1.67
Now when looking in the z table, we have that the corresponding value is 0.0475, that is, the probability is 4.75%
when sd = 0.2
z = (16 - 16.5) /0.2
z = -2.5
Now when looking in the z table, we have that the corresponding value is 0.0062, that is, the probability is 0.62%
when sd = 0
z = (16 - 16.5) / 0
z = infinity
probability cannot be calculated
