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SCORPION-xisa [38]
3 years ago
15

Estimate the line of best fit using two points on the line.

Mathematics
2 answers:
klasskru [66]3 years ago
7 0
The answer to this question is b
g100num [7]3 years ago
6 0

Answer:

D. y=10x

Step-by-step explanation:

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aleksandrvk [35]

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yes please

finals are killing me and i'm homeschooled so this is just hell

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
What is the sum? StartFraction 3 Over x squared minus 9 EndFraction StartFraction 5 Over x 3 EndFraction.
V125BC [204]

The sum of the two fractional number, which consist in the variable <em>x</em> is in the polynomial function,

f(x)=\dfrac{5x-12}{(x+3)(x-3)}

<h3>What is the sum of fraction number?</h3>

Fraction number is the number which is a part of a whole number. It is written with a numerator and denominator.

Fraction number are written as,

\dfrac{a}{b}

Here (a) is the numerator and (b) is the denominator.

To find the sum of two fraction numbers, cross multiply both the numbers or find the least common factor as denominator.

The first fraction number given in the problem is,

\dfrac{3}{x^2+9}

The second fraction number given in the problem is,

\dfrac{5}{x+3}

Let the sum of these number is f(x). Thus,

f(x)=\dfrac{3}{x^2-9}+\dfrac{5}{x+3}\\f(x)=\dfrac{3}{(x+3)(x-3)}+\dfrac{5}{x+3}\\

Solve it further as,

f(x)=\dfrac{3+5(x-3)}{(x+3)(x-3)}\\f(x)=\dfrac{3+5x-15}{(x+3)(x-3)}\\f(x)=\dfrac{5x-12}{(x+3)(x-3)}

Thus, the sum of the two fractional number is,

f(x)=\dfrac{5x-12}{(x+3)(x-3)}

Learn more about the fraction number here:

brainly.com/question/78672

6 0
2 years ago
Two fair coins are flipped. Given that at least one coin lands on a head, calculate the probability of one head and one tail. Wr
Greeley [361]

The probability of one head and one tail is 2/3.

<u>Step-by-step explanation</u>:

  • The possibilities for flipping two fair coins are {T,T}, {H,H}, {H,T}, {T,H}
  • Given the case that at least one coin lands on a head, So the total possibilities are {H,H}, {H,T}, {T,H} = 3 possibilities
  • Required event is 1 head and 1 tail= {H,T}, {T,H} = 2 possibilities

To calculate the probability of one head and one tail,

Probability = required events / Total events

Probability = 2/3

8 0
3 years ago
Factor completely 2x3 + x2 - 18x – 9.
lys-0071 [83]
2x^3+x^2-18x-9=x^2(2x+1)-9(2x+1)\\\\=(2x+1)(x^2-9)=(2x+1)(x^2-3^2)\\\\=(2x+1)(x-3)(x+3)
6 0
3 years ago
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HELPPPPPPP !!!!! Select the statements that are true based on the following given information.
almond37 [142]

the anwser is ]123[8D[

7 0
3 years ago
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