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4 years ago

8

Help with geometry work

1 answer:

AysviL [449]4 years ago

4 0

Can you ask me a Utah geometry

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Slope of j (0,0) , k (-2,8)

vichka [17]

I hope this helps you

8 0

3 years ago

Write the equation for a line that has an initial value of 3 and 3/4 as it’s rate of change

frutty [35]

the slope goes by several names

• average rate of change

• rate of change

• deltaY over deltaX

• Δy over Δx

• rise over run

• gradient

• constant of proportionality

however, is the same cat wearing different costumes.

initial value of 3, namely when x = 0, y = 3, so we have the point (0 , 3) and it has a rate or slope of 3/4.

$(\stackrel{x_1}{0}~,~\stackrel{y_1}{3})\qquad \qquad \stackrel{slope}{m}\implies \cfrac{3}{4} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{\cfrac{3}{4}}(x-\stackrel{x_1}{0})\implies y=\cfrac{3}{4}x+3$

3 0

3 years ago

No links, if ur right i’ll give u brainlist!!

abruzzese [7]

Answer:

answer is C. if im wrong just let me know :3

3 0

3 years ago

Solve the following system of equations using substitution:

iragen [17]

Answer:

x = -1

y = 2

Step-by-step explanation:

y = x+3

x+2y = 3

substitute y

x+2(x+3) = 3

simplify

3x+6 = 3

subtract 6 from both sides

3x = -3

x = -1

y = -1+3 = 2

6 0

3 years ago

A 30° 60° 90° triangle is shown below. Find the length of the side labeled y.

bulgar [2K]

Answer:

Part 1) $y=3\ units$

Part 2) The length of the hypotenuse is 6 units

Step-by-step explanation:

Part 1) we know that

In the right triangle of the figure

$sin(60^o)=\frac{y}{2\sqrt{3}}$ ----> by SOH (opposite side divided by the hypotenuse)

solve for y

$y=sin(60^o)2\sqrt{3}$

Remember that

$sin(60^o)=\frac{\sqrt{3}}{2}$

substitute

$y=(\frac{\sqrt{3}}{2})2\sqrt{3}$

$y=3\ units$

Part 2)

Let

h ----> the length of the hypotenuse

we know that

In the right triangle of the figure

$sin(45^o)=\frac{3\sqrt{2}}{h}$ ----> by SOH (opposite side divided by the hypotenuse)

$h=\frac{3\sqrt{2}}{sin(45^o)}$

Remember that

$sin(45^o)=\frac{\sqrt{2}}{2}$

substitute

$h=3\sqrt{2}:\frac{\sqrt{2}}{2}$

$h=6\ units$

7 0

3 years ago