We first need to find the radius of the circle, so we need to do 8π/π which gives us a diameter of 8 cm, halving this gives us a radius of 4 cm.
The area of this circle will be:
A = πr^2
A = 4^2
A = 16π cm^2
Now to find the volume we simply multiply the area by the height:
16π × 7 = 112π cm^3 which is our final answer.
Hope this helps!!!!!!!!!!
1) 2 with a small 4 at the top like an exponent
Given:
The zeros of the polynomial are
.
Degree = 4
Leading coefficient = 1
To find:
The polynomial.
Solution:
If c is a zero of a polynomial, then (x-c) must be a factor of the polynomial.
Here, -2,4,-5, 5, are zeros of the required polynomial, so (x+2), (x-4), (x+5), (x-5) are factors of required polynomial.

![[\because a^2-b^2=(a-b)(a+b)]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5E2-b%5E2%3D%28a-b%29%28a%2Bb%29%5D)

Using distributive property, we get


On combining like terms, we get


Here, the leading coefficient is 1. So, it is the required polynomial.
Therefore, the correct option is E.