Question

A ball is thrown from an initial height of 2 feet with an initial upward velocity of 18/fts . The ball's height h (in feet) after t seconds is given by the following. =h+2−18t16t^2 Find all values of t for which the ball's height is 6 feet. Round your answer(s) to the nearest hundredth.
PLEASE SOMEONE HELP

Answer 1

Hello! First insert 6 where the h is located. So we have an equation that looks like the following. $6 = 2 - 18t + 16t^2$

Although you could leave the equation in its original form, I am going to switch it around.
$6 = 2 - 18t + 16t^2$
$16t^2 - 18t + 2 = 6$
Move the 6 to the other side and do the math
$16t^2 - 18t + 2 - 6 = 6 - 6$
$16t^2 - 18t -4 = 0$
Factor and after factoring your T will be as follows
t = $\frac{9}{16} - \frac{\sqrt{145}}{16}$ = -0.1900
t = $\frac{9}{16} + \frac{\sqrt{145}}{16}$ = 1.315