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AleksandrR [38]

3 years ago

9

An oil spill spreads 25 square meters every 1/6 hour. How much area does the oil spill cover after 2 hours

1 answer:

Varvara68 [4.7K]3 years ago

4 0

It will 300 in two hours at that rate

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What fraction is at the same location as 1/4

Maksim231197 [3]

Answer:

Fractions equivalent to 1/4 are 2/8, 3/12, 4/16, 5/20, 6/24, 7/28, 8/32, 9/36, 10/40.

those are the ones i know so far

3 0

3 years ago

What is an equation of the line that passes through the points (4, -6)<br>and (8, -4)

QveST [7]

$\bf (\stackrel{x_1}{4}~,~\stackrel{y_1}{-6})\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{-4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-4}-\stackrel{y1}{(-6)}}}{\underset{run} {\underset{x_2}{8}-\underset{x_1}{4}}}\implies \cfrac{-4+6}{4}\implies \cfrac{2}{4}\implies \cfrac{1}{2}$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-6)}=\stackrel{m}{\cfrac{1}{2}}(x-\stackrel{x_1}{4}) \\\\\\ y+6=\cfrac{1}{2}x-2\implies y=\cfrac{1}{2}x-8$

3 0

3 years ago

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Find the sum and express it in simplest form. (ab+4a-6)+(ab+6)

riadik2000 [5.3K]

= 2ab + 4a + 6 - 6

= 2ab + 4a

you can factor this to 2a(b + 2)

3 0

3 years ago

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What is the nth term rule of the linear sequence below?<br> -9, -5, -1, 3, 7,...

Amiraneli [1.4K]

Answer:

11,15,19,23,27,31,35,39,43,47,51,....

6 0

3 years ago

Which expression is equivalent to RootIndex 3 StartRoot 32 x Superscript 8 Baseline y Superscript 10 Baseline EndRoot?

evablogger [386]

Answer:

The equivalent expression to the given expression is $\sqrt[3]{32x^8y^{10}}=2x^2y^3\sqrt[3]{4x^2y}$

Step-by-step explanation:

The given expression is $\sqrt[3]{32x^8y^{10}}$

To find the equivalent expression:

$\sqrt[3]{32x^8y^{10}}=(32x^8y^{10})^{\frac{1}{3}}$

We may write the above expression as below:

$=(32^{\frac{1}{3}})((x^8)^{\frac{1}{3}})((y^{10})^{\frac{1}{3}})$

$=(2)((4)^{\frac{1}{3}})(x^6)\times (x^2)(x^{\frac{2}{3}})(y^3)(y^{\frac{1}{3}})$ (using square root properties)

$=(2\sqrt[3]{4})(x^2\sqrt[3]{x^2})(y^3\sqrt[3]{y})$ (combining the like terms and doing multiplication )

$=2x^2y^3\sqrt[3]{4x^2y}$

Therefore $\sqrt[3]{32x^8y^{10}}=2x^2y^3\sqrt[3]{4x^2y}$

Therefore the equivalent expression to the given expression is $\sqrt[3]{32x^8y^{10}}=2x^2y^3\sqrt[3]{4x^2y}$

5 0

3 years ago

Read 2 more answers