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nikitadnepr [17]
3 years ago
13

Which rule describes the composition of transformations

Mathematics
2 answers:
choli [55]3 years ago
4 0

Answer:

a reflection and then a translation

Step-by-step explanation:

Aleks [24]3 years ago
4 0

Answer:

R B', 270 ○ rₘ

Step-by-step explanation:

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2 2/9+ 3 3/7 +1 4/9 enter sum in a box as a mixed number in simplest form
viva [34]

Answer:

Input Data :

Mixed Fraction A =  

7

1

6

Mixed Fraction B =  

2

1

3

Step-by-step explanation:

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4 0
3 years ago
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Can I please have help me with this problem ​
guajiro [1.7K]

9514 1404 393

Answer:

  B, C

Step-by-step explanation:

Shelby's total earnings will be the sum of the amount she has earned and the amount she can earn working h hours. That latter amount is 25h, since she makes $25 per hour. She wants that total to be at least $2000.

  75 + 25h ≥ 2000

Dividing by 25 gives ...

  3 +h ≥ 80

subtracting 3, we have ...

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These match options B and C of your list.

8 0
3 years ago
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7 0
3 years ago
Multiple Choice<br> Evaluate.<br> 1. -59 - 6 for g=-2 (1 point)<br> A.4<br> B.16<br> C.10<br> D.-13
Sergeeva-Olga [200]
Answer: A. 4

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4 0
4 years ago
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How many ways can eight letters be arranged into groups of five where order matters and the first two letters are already chosen
fenix001 [56]

Answer:

120

Step-by-step explanation:

Since we're dealing with a problem where the order matters and the first two letters are already chosen we need to subtract the number of letters and the number of available slots per group.

We use the permutation formula to find the answer, but before that let's check values.

n = 8

k = 5

Now since there are two letters already chosen we have to deduct two from both the value of n and k.

n = 6

k = 3

Now we can use the permutation formula:

_{n}P_{k}=\dfrac{n!}{(n-k)!}

_{6}P_{3}=\dfrac{6!}{6-3)!}

_{6}P_{3}=\dfrac{6!}{3!}

_{6}P_{3}=\dfrac{6*5*4*3*2*1}{3*2*1}

The 3*2*1 cancels out and leaves us with:

_{6}P_{3}=6*5*4

_{6}P_{3}=120

So there are 120 possible ways to arrange eight letters into groups of five where order matters and the first two letters are already chosen.

6 0
3 years ago
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