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3 years ago

When you flip a biased coin the probability of getting a tail is 0.42.

Mathematics

1 answer:

ddd [48]3 years ago

8 0

Answer:

0.58 or 58%

Step-by-step explanation:

If the highest probability is 1, and you already have 0.42, you have to find what is left, so our equation is:

1 - 0.41 = 0.58

So the probability of getting a head is 0.58 or 58%

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Which symbol correctly compares these fractions? 13 20 ___ 7 10

fomenos

These are fractions? Like 13/20 and 7/10? Is so the symbol would be 13/20 < 7/10 because 7/10 is a higher fraction than 13/20

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3 years ago

Read 2 more answers

Which expression is equivalent to

tankabanditka [31]

144^(3/2) = √(144^3) = 1,728

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3 years ago

HELPP!! Points A and B are on the different sides on line l, the distance between point A and the line l is 10 in, the distance

ss7ja [257]

Answer:

Step-by-step explanation:

each way from 10 to 7 is 3 and 4 to 7 is 4

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3 years ago

Which equation represents a line that intersects the line 2y − 4x = 3? A.-2y + 4x = 1 B. 3y − 6x = 6.5 C. y − 2x = 3 D. -2y − 4x

irga5000 [103]

Convert all the equations to slope-intercept form:
$2y-4x=3 \ \ \ |+4x \\
2y=4x+3 \ \ \ |\div 2 \\
y=2x+\frac{3}{2}$

$A. \\
-2y+4x=1 \ \ \ |-4x \\
-2y=-4x+1 \ \ \ |\div (-2) \\
y=2x-\frac{1}{2} \\ \\
B. \\
3y-6x=6.5 \ \ \ |+6x \\
3y=6x+6.5 \ \ \ |\div 3 \\
y=2x+\frac{13}{6}$

$C. \\
y-2x=3 \ \ \ |+2x \\
y=2x+3 \\ \\
D. \\ 
-2y-4x=3 \ \ \ |+4x \\
-2y=4x+3 \ \ \ |\div (-2) \\
y=-2x-\frac{3}{2}$

Lines A, B and C have the same slope as the line 2y-4x=3, so they are parallel and don't intersect it.
Line D has another slope, so it intersects the line 2y-4x=3.
The answer is D.

3 0

3 years ago

A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective. Step 2 of 2 :

const2013 [10]

Answer:

The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

Suppose a sample of 1067 floppy disks is drawn. Of these disks, 74 were defective.

This means that $n = 1067, \pi = \frac{74}{1067} = 0.069$

80% confidence level

So $\alpha = 0.2$ , z is the value of Z that has a pvalue of $1 - \frac{0.2}{2} = 0.9$ , so $Z = 1.28$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 - 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.059$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 + 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.079$

The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).

7 0

2 years ago