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LenKa [72]
3 years ago
7

The function g(x)=(x-2^2. The function f(x)=g(x) +3

Mathematics
1 answer:
OlgaM077 [116]3 years ago
4 0
The parent function is:
 y = x ^ 2
 Applying the following function transformation we have:
 Horizontal translations:
 Suppose that h> 0
 To graph y = f (x-h), move the graph of h units to the right.
 We have then:
 g (x) = (x-2) ^ 2
 Then, we have the following function transformation:
 Vertical translations
 Suppose that k> 0
 To graph y = f (x) + k, move the graph of k units up.
 We have then that the original function is:
 g (x) = (x-2) ^ 2
 Applying the transformation we have
 f (x) = g (x) +3
 f (x) = (x-2) ^ 2 + 3
 Answer:
 
the function f(x)  moves horizontally 2 units rigth.
 
The function f (x) is shifted vertically 3 units up.
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Answer:

<u>The student's final score is 77.2 and he earned a C letter grade</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the math problem correctly:

Midterm = 5% of the final grade and score of 60

Class project = 10% of the final grade and score of 92

Set of homework = 35% of the final grade and score of 80

Final exam = 50% of the final grade and score of 74

2. What is the student's final score?

Final score = (60 * 0.05) + (92 * 0.1) + (80 * 0.35) + (74 * 0.5)

Final score = 3 + 9.2 + 28 + 37

Final score = 77.2 and letter grade of C

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3 years ago
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Answer:

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4 0
2 years ago
Is this the right answer??
nordsb [41]

Answer:

yes

Step-by-step explanation:

If there are no horizontal points on the graph that are even with other horizontal points on the graph, then the graph is a function.

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3 years ago
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Katen [24]

Answer:

10 and 15

Step-by-step explanation:

Let 'x' and 'y' are the numbers we need to find.

x + y = 25 (two numbers whose sum is 25)

(1/x) + (1/y) = 1/6 (the sum of whose reciprocals is 1/6)

The solutions of the this system of equations are the numbers we need to find.

x = 25 - y

1/(25 - y) + 1/y = 1/6 multiply both sides by 6(25-y)y

6y + 6(25-y) = (25-y)y

6y + 150 - 6y = 25y - (y^2)

y^2 - 25y + 150 = 0 quadratic equation has 2 solutions

y1 = 15

y2 = 10

Thus we have :

First solution: for y = 15, x = 25 - 15 = 10

Second solution: for y = 10, x = 25 - 10 = 15

The first and the second solution are in fact the same one solution we are looking for: the two numbers are 10 and 15 (since the combination 10 and 15 is the same as 15 and 10).

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