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2 years ago

First come first served brainiest:)

Mathematics

1 answer:

adoni [48]2 years ago

5 0

Answer:

1. Not proportional 2. is proportional. For 3, 4, 5, and 6 just plot them.

Step-by-step explanation:

For 1, y intercept/x intercept is not 0 when you graph, thus not proportional. Number 2 is, thus proportional. For 3, 4, 5, and 6 you would plot them accordingly. So for (-5, -2) Start as 0,0 and go 5 to the left as it's negative, and 2 down as it is also negative. Do the same for others.

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Evgen [1.6K]

Answer:

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2 years ago

Find a polynomial function of degree 3 with 2, i, -i as zeros.

sergiy2304 [10]

Answer:

$p(x)= x^3-2x^2+x-2$

Step-by-step explanation:

Here we are given that a polynomial has zeros as 2 , i and -i . We need to find out the cubic polynomial . In general we know that if $\alpha , \ \beta \ \& \ \gamma$ are the zeros of the cubic polynomial , then ,

$\sf \longrightarrow p(x)= (x -\alpha )(x-\beta)(x-\gamma)$

Here in place of the Greek letters , substitute 2,i and -i , we get ,

$\sf\longrightarrow p(x)= (x -2 )(x-i)(x+i)$

Now multiply (x-i) and (x+i ) using the identity (a+b)(a-b)=a² - b² , we have ,

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Simplify using i = √-1 ,

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Multiply by distribution ,

$\sf \longrightarrow p(x)= x(x^2+1) -2(x^2+1)$

Simplify by opening the brackets ,

$\sf\longrightarrow p(x)= x^3+x-2x^2-2$

Rearrange ,

$\sf\longrightarrow \underline{\boxed{\blue{\sf p(x)= x^3-2x^2+x-2}}}$

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2 years ago

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