Answer:
Question plzzzzzz to answer
<em><u>your </u></em><em><u>question:</u></em><em><u> </u></em>
<em>374 students and there are 4 boys to every 7 girls. How many </em><em>boys?</em>
<em><u>answer:</u></em><em><u> </u></em>
<em>1</em><em>3</em><em>6</em><em> </em><em>boys </em>
Let present age of women and her daughter be x and y respectively.
<u>According to the questi</u>on,
Case 1 :
Two years ago,
Woman age = ( x - 2 ) years
Her daughter age = ( y - 2 ) years
Woman was 7 times old as her daughter. [ Given ]
x - 2 = 7 ( y - 2 )
=> x - 2 = 7y - 14
=> x - 2 + 14 = 7y
=> x + 12 = 7y ....( i )
Case 2 :
After Three years ,
Woman age = x + 3
Her daughter age = y + 3
she would be 4 times old as the girl. [ Given ]
x + 3 = 4 ( y + 3 )
=> x + 3 = 4y + 12
=> x = 4y + 12 - 3
=> x = 4y + 9....( ii )
Now,
★ Substituting the value of x = 4y + 9 from equation ( ii ) in equation ( i ),we get
x + 12 = 7y
=> 4y + 9 + 12 = 7y
=> 21 = 7y - 4y
=> 21 = 3y
=> 3y = 21
=> y = 21/3
=> y = 7
And,
x = 4y + 9
★ Substituting the value of y in equation ( ii ), we get
x = 4 × 7 + 9
x = 28 + 9
x = 37
Hence, the present age of women is 37 years and her daughter age is 7.
Answer:
C D and E
Step-by-step explanation:
