20x+3
This shouldddd be the answer sorry if I’m wrong, but if you group all the x variables together they add up to twenty, then you just add “+3” being that it has no x and therefore must be put in some form of separate group!
T = (1/0.03) [(8050/7000)-1]
t = 33.33 * 0.15
t= 5 yrs
18, 23, 24 I think so not sure
Answer:
Suppose that in the inventory problem, the storage cost depends on the maximum inventory size, rather than the average. This would be more realistic if, for example, the company had to build a warehouse large enough to hold the maxi- mum inventory, and the cost of storage was the same no matter how full or empty the warehouse was. Show that in this case the number of units that should be ordered or manufactured to minimize the total cost is q= âfM/k
Step-by-step explanation:
Suppose that in the inventory problem, the storage cost depends on the maximum inventory size, rather than the average. This would be more realistic if, for example, the company had to build a warehouse large enough to hold the maxi- mum inventory, and the cost of storage was the same no matter how full or empty the warehouse was. Show that in this case the number of units that should be ordered or manufactured to minimize the total cost is q= âfM/k
Answer:
(3,-3)
Step-by-step explanation:
First you divide 2 out of the first equation and it turns into 5x+y=12.
Then you write one on top of the other so you can add them. It looks like:
5x + y = 12
-5x + y = -18
Then you add them together and the 5x's cancel each other out and you are left with 2y = -6
So then you divide both sides by 2 and get y = -3
Then you plug -3 into the second equation because it is simpler and get -5x - 3 = -18
So then you add three to both sides and get -5x = -15
And finally you divide both sides by -5 and get x=3
