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2 years ago

6+8(y-3/5), if y=8/9

Mathematics

2 answers:

Alexeev081 [22]2 years ago

8 0

Answer:

<em>8 14/45</em>

Step-by-step explanation:

First, place 8/9 anywhere there is a y:

6+8(8/9-3/5)

Next, do what is in the parenthesis. Make both fractions have the same denominator.

6+8(40/45-27/45)

And now subtract:

6+8(13/45)

Now, multiply 8 and 13/45:

6+ 104/45

Convert the fraction to a mixed fraction:

2 14/45

Finally, add 6:

8 14/45

<h3>Hopefully I helped :)</h3>

igor_vitrenko [27]2 years ago

4 0

8 14/45 is your best answer

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3 years ago

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3 years ago

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with $0\le t\le1$ .

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$\displaystyle\int_C\vec F(x,y)\cdot\mathrm d\vec r=\int_0^1\vec F(x(t),y(t))\cdot\frac{\mathrm d\vec r(t)}{\mathrm dt}\,\mathrm dt$

$=\displaystyle\int_0^1(-2t\,\vec\imath+(5-5t)\,\vec\jmath)\cdot(-5\,\vec\imath+2\,\vec\jmath)\,\mathrm dt$

$=\displaystyle\int_0^1(10t+(10-10t))\,\mathrm dt$

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d. Notice that we can write the line integral as

$\displaystyle\int_C\vecF\cdot\mathrm d\vec r=\int_C(-y\,\mathrm dx+x\,\mathrm dy)$

By Green's theorem, the line integral is equivalent to

$\displaystyle\iint_D\left(\frac{\partial x}{\partial x}-\frac{\partial(-y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=2\iint_D\mathrm dx\,\mathrm dy$

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2 years ago