All categories

3 years ago

6+8(y-3/5), if y=8/9

Mathematics

2 answers:

Alexeev081 [22]3 years ago

8 0

Answer:

<em>8 14/45</em>

Step-by-step explanation:

First, place 8/9 anywhere there is a y:

6+8(8/9-3/5)

Next, do what is in the parenthesis. Make both fractions have the same denominator.

6+8(40/45-27/45)

And now subtract:

6+8(13/45)

Now, multiply 8 and 13/45:

6+ 104/45

Convert the fraction to a mixed fraction:

2 14/45

Finally, add 6:

8 14/45

<h3>Hopefully I helped :)</h3>

igor_vitrenko [27]3 years ago

4 0

8 14/45 is your best answer

You might be interested in

Kristen can run at 9kmh-1 and walk at 3kmh-1. She completed a 42km marathon in 6 hours. What distance did Kristen run during the

Hatshy [7]

Kristen completed 42 km. We will imagine that she ran all 6 hours. => 9 * 6 =54 km which is more than she actually completed. So we will find a 9 Multiple less than 42 km and that will be 36 km. (9 * 4 = 36 km completed by running) and the rest until 42 were completed by walking (3 * 2 = 6; 6 + 36 =42).

6 0

3 years ago

13y-7y=9<br> Solve for y, write it as a reduced fraction.

raketka [301]

Answer:

3/2 OR 1 1/2

Step-by-step explanation:

Collect like terms, meaning combine both y's. You should have something like this afterwards.

6y = 9

Now that you have that divide the 6 on both sides so Y is by itself!

Your answer is now 3/2.

4 0

2 years ago

What is the solution to the equation 4w=2/3?

nikdorinn [45]

Answer:

2/12

Step-by-step explanation:

4w=2/3

1/4(4w)=1/4 x 2/3

w=2/12

6 0

3 years ago

Please answer if you can.

Mumz [18]

Answer:

25+24= 49coins 49÷2.5 is 19.5 so there are 19.5 dimes in the bag I believe

7 0

3 years ago

F⃗ (x,y)=−yi⃗ +xj⃗ f→(x,y)=−yi→+xj→ and cc is the line segment from point p=(5,0)p=(5,0) to q=(0,2)q=(0,2). (a) find a vector pa

DerKrebs [107]

a. Parameterize $C$ by

$\vec r(t)=(1-t)(5\,\vec\imath)+t(2\,\vec\jmath)=(5-5t)\,\vec\imath+2t\,\vec\jmath$

with $0\le t\le1$ .

b/c. The line integral of $\vec F(x,y)=-y\,\vec\imath+x\,\vec\jmath$ over $C$ is

$\displaystyle\int_C\vec F(x,y)\cdot\mathrm d\vec r=\int_0^1\vec F(x(t),y(t))\cdot\frac{\mathrm d\vec r(t)}{\mathrm dt}\,\mathrm dt$

$=\displaystyle\int_0^1(-2t\,\vec\imath+(5-5t)\,\vec\jmath)\cdot(-5\,\vec\imath+2\,\vec\jmath)\,\mathrm dt$

$=\displaystyle\int_0^1(10t+(10-10t))\,\mathrm dt$

$=\displaystyle10\int_0^1\mathrm dt=\boxed{10}$

d. Notice that we can write the line integral as

$\displaystyle\int_C\vecF\cdot\mathrm d\vec r=\int_C(-y\,\mathrm dx+x\,\mathrm dy)$

By Green's theorem, the line integral is equivalent to

$\displaystyle\iint_D\left(\frac{\partial x}{\partial x}-\frac{\partial(-y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=2\iint_D\mathrm dx\,\mathrm dy$

where $D$ is the triangle bounded by $C$ , and this integral is simply twice the area of $D$ . $D$ is a right triangle with legs 2 and 5, so its area is 5 and the integral's value is 10.

4 0

2 years ago