Answer:
Step-by-step explanation:
2.
Because we don't know how many crayons he bought we will call it c.
c = total number of crayons purchased
T = total number of crayons each student gets
To determine how many crayons each student gets we divide c by 32, because that's the number of students in his class.
c / 32 = T
So let's say he purchased 120 crayons.
c = 120
120/32 = T
T = 3.75
Since he can't give a fraction of a crayon, in this case, each student will get 3 crayons.
3.
We will now pretend there are 24 crayons in 1 box.
So T still equals the total number of crayons each student gets and c still equals number of crayons purchased, but now we also have b which equals the number of crayons in 1 box.
c = total number of crayons purchased
T = total number of crayons each student gets
b = number of crayons in 1 box
x = number of boxes purchased
So b*x = c
We can still write the equation:
c / 32 = T
We know T = 12 So we plug 12 in for T
c / 32 = 12 Now multiply each side by 32, so 32 will cancel on the left.
32c/32 = 12 * 32
c = 12 * 32
c = 384
So if he needs to purchase 384 crayons we can use our other equation.
b*x = c
b = 24
c = 384
So we plug those in.
24x = 384 Divide each side by 24 so 24 will cancel on the left.
24x/24 = 384/24
x = 384/24
x = 16
So he needs to buy 16 boxes of crayons in this instance. We can figure out how many boxes he bought in #2 by using the same equation.
b*x = c
c = 120 in #2
b =24
24 * x = 120
24x/24 = 120/24
x = 120/24
x = 5
So for each student to have 12 crayons he needs to purchase 11 more boxes (16 - 5 = 11).
This will work for whatever numbers you were given.
Remember:
c = total number of crayons purchased
T = total number of crayons each student gets
b = number of crayons in 1 box
x = number of boxes purchased
b*x = c
c / 32 = T
