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NNADVOKAT [17]
3 years ago
12

A business owner buys lunch for employees once every month. The owner has bought lunch for 18

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
6 0

Answer:

A) y = 8.63 x

B) $224.38

Step-by-step explanation:

The the average monthly cost = (147.98+152.17+165.63)/3 = $155.26

So, For 18 employees the average monthly cost = $155.26

Let the equation that can be used to estimate y, the average monthly cost, in dollars, to buy lunch for x employees. ⇒ y = mx

For x = 18 , y = $155.26

So, m = y/x = $155.26/18 ≈ $8.63

∴ y = 8.63 x

To find the total cost for 26 employees.

∴ x = 26

∴ y = 8.63 * 26 = 224.38

The total cost of a monthly lunch for 26 employees = $224.38

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We're looking for a solution of the form

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Given the complexity of this recursive definition, it's unlikely that you'll be able to find an exact solution to this recurrence. (You're welcome to try. I've learned this the hard way on scratch paper.) So instead of trying to do that, you can compute the first few coefficients to find an approximate solution. I got, assuming initial values of y(0)=y'(0)=1, a degree-8 approximation of

y(x)\approx1+x-\dfrac{x^3}3+\dfrac{x^4}3+\dfrac{x^5}2-\dfrac{16x^6}{45}-\dfrac{79x^7}{125}+\dfrac{101x^8}{210}

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