We can solve this using substitution.
because x-y=2.5
x=y+2.5
Now substitute x into other equation.
2(y+2.5)^2-2y=125
2y^2+10y+12.5-2y=125
2y^2+8y-112.5=0
Now comes the ugly part
y=-4+-sqrt(16+900)
y=-4+-sqrt916
y=-4+-2sqrt229
x=-1.5+-2sqrt229
Answer:
One of the cylinders is short and wide, while the other is tall and thin.
Step-by-step explanation:
In item# 1, we are only given with the height of the tree a=15 meters and we are asked to solve for the hypotenuse. Since we are not given with angle created between the rope the ground level we will assign it as ∠A = ∅
Solving for the length of the rope, we have
sin A = 15/Length of rope
Length of rope = 15 meters / sin A
In item#2, assuming that it is a right triangle we have:
8 ²= x²+3.5²
x=7.2
The smallest angle:
sin Z =3.5/8
Z = 25.95°
