<span>The
content of any course depends on where you take it--- even two courses
with the title "real analysis" at different schools can cover different
material (or the same material, but at different levels of depth).
But yeah, generally speaking, "real analysis" and "advanced calculus"
are synonyms. Schools never offer courses with *both* names, and
whichever one they do offer, it is probably a class that covers the
subject matter of calculus, but in a way that emphasizes the logical
structure of the material (in particular, precise definitions and
proofs) over just doing calculation.
My impression is that "advanced calculus" is an "older" name for this
topic, and that "real analysis" is a somewhat "newer" name for the same
topic. At least, most textbooks currently written in this area seem to
have titles with "real analysis" in them, and titles including the
phrase "advanced calculus" are less common. (There are a number of
popular books with "advanced calculus" in the title, but all of the ones
I've seen or used are reprints/updates of books originally written
decades ago.)
There have been similar shifts in other course names. What is mostly
called "complex analysis" now in course titles and textbooks, used to be
called "function theory" (sometimes "analytic function theory" or
"complex function theory"), or "complex variables". You still see some
courses and textbooks with "variables" in the title, but like "advanced
calculus", it seems to be on the way out, and not on the way in. The
trend seems to be toward "complex analysis." hope it helps
</span>
Answer:
The rate of the jet in still air is 738 mph and the rate of the wind is 90 mph
Step-by-step explanation:
Check: (738+90)*6 = 648*6 = 3888 mike's against the wind
(738-90)*6 = 828*6 = 4968 miles with the wind
Equation is rate = distance divided by time. So it’s 8 miles divided by how many hours. 8/4/5.
It’s the last one. D.
Answer:
Step-by-step explanation:
I think the median you are asking is the middle value,
because there is a total of 20 vehicles, there are two middle number: 31 and 31.
To solve this:
you first plus these two numbers together, you will get 62.
then divide them by 2, then you will get the middle number.
the middle number will be 31. ( actually because theese two number are the same, you do not really need to plus them then divide by 2, you could just answer the question 31, but because when you do other question and has the same situation but not the same number, (suppose you got 20 and 21) Then you need to do this question like I said above)
I wish this could help you.
