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Bas_tet [7]
3 years ago
6

Judith Thompson, the manager of the student center cafeteria, has added pizza to the menu. The pizza is ordered frozen from a lo

cal pizza establishment and baked at the cafeteria. Judith anticipates a weekly demand of 10 pizzas. The cafeteria is open 45 weeks a year, 5 days a week. The ordering cost is $15 and the holding cost is $0.40 per pizza per year. The pizza vendor has a 4-day lead-time and Judith wants to maintain 1 pizza for safety stock. What is the optimal reorder point
Business
1 answer:
erica [24]3 years ago
6 0

Answer:

9 pizzas

Explanation:

Given that:

A pizza is ordered frozen from a local pizza establishment and baked at the cafeteria.

Judith anticipates a weekly demand of 10 pizzas.

Opening weeks in a year = 45 weeks

Opening days in a week = 5 days

Daily demand =  10/5 = 2

Ordering cost = $15

Holding cost = $0.40 /pizza/year

Lead time = 4 days

Safety stock = 1 pizza

The objective is to determine the optimal reorder point.

The optimal reorder point = (daily demand × lead time) + safety stock

The optimal reorder point =( 2 × 4 ) + 1

The optimal reorder point = 8 + 1

The optimal reorder point = 9 pizzas

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Answer:

The ticket price that maximizes revenue is $18.10

Explanation:

Hi, first we need to construct the revenue equation in terms of the additional dollar charge (that would be X). That is:

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So we expand it:

Revenue=15,300-552.5X+1,800X-65X^{2}

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This is a parabola, and we need to find its vertex, which in our case that would be the maximum additional dollar charge in order to obtain the highest revenue possible, to find the vertex, we need to consider that:

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And to find the X-coordenate we have to use the following equation.

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In our case, A= -65; B= 1,247.5, so, all should look like this:

Vertex (X)=\frac{-(1247.50}{2(-65)} =9.6

That means, we need to make 9.6 increments of $1 in order to obtain the max revenue possible, therefore, the price would be

Price = $8.50 + $1(9.6)= $8.50 + $9.6 =$18.10

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7 0
3 years ago
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