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3 years ago

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What are two forms of expanded notation 0.58 using fractions

1 answer:

victus00 [196]3 years ago

6 0

Answer:

Step-by-step explanation:

Don’t know

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The system shown has the unique solution (2, y, z). Solve the system and select the values that complete the solution. y = 0 y =

madreJ [45]

So we are given a system:
$3x-2y+3z=0\\
-3x - 5y - 5z= -21$
Substitute x = 2 we get the system:
$-2y+3z=-6\\
- 5y - 5z= -15$
Multiply the first equation by -5 and the second by 2 we get the system:
$10y-15z=30\\
- 10y - 10z= -30$
Adding the two equations we get :
$-25z=0\text{ then}z=0.$
We find the value of y by using any of the other equations like this:
$-2y=-6\\y=3.$
Final solution:
$z=0,y=3$

8 0

2 years ago

Read 2 more answers

This one is algebra.....

vodomira [7]

${Hello~!\:}$

<h2>Your answer will be is :</h2><h2></h2><h3>B. And C.</h3><h3></h3>

Hope It Helps. . .

#LearnWithBrainly

$\underline{A~n~s~w~e~r~:\;}$

$\bold{Jace\;}$ ^-^

7 0

2 years ago

Diego is solving the equation x^2-12x = 21

uysha [10]

Answer:

The solutions to the quadratic equations will be:

$x=\sqrt{57}+6,\:x=-\sqrt{57}+6$

Step-by-step explanation:

Given the expression

$x^2-12x\:=\:21$

Let us solve the equation by completing the square

$x^2-12x\:=\:21$

Add (-6)² to both sides

$x^2-12x+\left(-6\right)^2=21+\left(-6\right)^2$

simplify

$x^2-12x+\left(-6\right)^2=57$

Apply perfect square formula: (a-b)² = a²-2ab+b²

i.e.

$x^2-12x+\left(-6\right)^2=\left(x-6\right)^2$

so the expression becomes

$\left(x-6\right)^2=57$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x-6=\sqrt{57}$

add 6 to both sides

$x-6+6=\sqrt{57}+6$

Simplify

$x=\sqrt{57}+6$

also solving

$x-6=-\sqrt{57}$

add 6 to both sides

$x-6+6=-\sqrt{57}+6$

Simplify

$x=-\sqrt{57}+6$

Therefore, the solutions to the quadratic equation will be:

$x=\sqrt{57}+6,\:x=-\sqrt{57}+6$

5 0

2 years ago

Simplify the following? (x^5)^4

Elis [28]

X^20 i hope this helps

8 0

3 years ago

Find the length of the hypotenuse of a right triangle whose legs are 3 and square root of 2.

madreJ [45]

Square root of 11 because:
sqrt2^2 = 2
3^2 = 9
so C^2 or the hypotenuse would be the square root of 11

6 0

3 years ago