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g100num [7]
3 years ago
11

What are two forms of expanded notation 0.58 using fractions

Mathematics
1 answer:
victus00 [196]3 years ago
6 0

Answer:

Step-by-step explanation:

Don’t know

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The system shown has the unique solution (2, y, z). Solve the system and select the values that complete the solution. y = 0 y =
madreJ [45]
So we are given a system:
3x-2y+3z=0\\
-3x - 5y - 5z= -21
Substitute x = 2 we get the system:
-2y+3z=-6\\
- 5y - 5z= -15
Multiply the first equation by -5 and the second by 2 we get the system:
10y-15z=30\\
- 10y - 10z= -30
Adding the two equations we get :
-25z=0\text{ then}z=0.
We find the value of y by using any of the other equations like this:
-2y=-6\\y=3.
Final solution:
z=0,y=3
8 0
2 years ago
Read 2 more answers
This one is algebra.....
vodomira [7]

{Hello~!\:}

<h2>Your answer will be is :</h2><h2></h2><h3>B. And C.</h3><h3></h3>

Hope It Helps. . .

#LearnWithBrainly

\underline{A~n~s~w~e~r~:\;}

\bold{Jace\;} ^-^

7 0
2 years ago
Diego is solving the equation x^2-12x = 21
uysha [10]

Answer:

The solutions to the quadratic equations will be:

x=\sqrt{57}+6,\:x=-\sqrt{57}+6

Step-by-step explanation:

Given the expression

x^2-12x\:=\:21

Let us solve the equation by completing the square

x^2-12x\:=\:21

Add (-6)² to both sides

x^2-12x+\left(-6\right)^2=21+\left(-6\right)^2

simplify

x^2-12x+\left(-6\right)^2=57

Apply perfect square formula: (a-b)² = a²-2ab+b²

i.e.

x^2-12x+\left(-6\right)^2=\left(x-6\right)^2

so the expression becomes

\left(x-6\right)^2=57

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

solve

x-6=\sqrt{57}

add 6 to both sides

x-6+6=\sqrt{57}+6

Simplify

x=\sqrt{57}+6

also solving

x-6=-\sqrt{57}

add 6 to both sides

x-6+6=-\sqrt{57}+6

Simplify

x=-\sqrt{57}+6

Therefore, the solutions to the quadratic equation will be:

x=\sqrt{57}+6,\:x=-\sqrt{57}+6

5 0
2 years ago
Simplify the following? (x^5)^4​
Elis [28]
X^20 i hope this helps
8 0
3 years ago
Find the length of the hypotenuse of a right triangle whose legs are 3 and square root of 2.
madreJ [45]
Square root of 11 because:
sqrt2^2 = 2
3^2 = 9 
so C^2 or the hypotenuse would be the square root of 11 
6 0
3 years ago
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