All categories

3 years ago

what is the mean absolute deviation of the following numbers 18,28,24,25,15.

Mathematics

1 answer:

horsena [70]3 years ago

3 0

Answer:

4.4

Step-by-step explanation:

You might be interested in

5/8 divided by 3/10. Can the answer be a fraction in simplest form.

charle [14.2K]

Answer:

2 1/12

Step-by-step explanation:

50/80 x 80/24 =

4000/1920 =

2 160/1920 =

2 16/192 =

2 8/96 =

2 2/24 =

2 1/12

Hope this helps! Please mark as brainliest.

4 0

3 years ago

Read 2 more answers

Which one? Helppppppp

Nat2105 [25]

Answer:

second one

Step-by-step explanation:

7 0

3 years ago

Plz do have mercy and help me

Nikitich [7]

I have mercy:

8x and 9x+5 (the angles) form a right angle so 8x+9x+5=90 which means x is 5 and plugging it back into the angles 8x we get 40 sinceBHR and angle 8x are vertical angles they are equal to each other and so it's equal to 40

4 0

3 years ago

Anthony wants to make two different rectangular flowerbeds ,each with an area of 24 square feet .he will build a wooden frame ar

nignag [31]

One of them is 3,8,3,8 and the other is 4,6,4,6

3 0

4 years ago

Read 2 more answers

REY [17]

The true statement about the graph of the function f(x) = x3 - 2x2 + 4x – 8 is (B) The function has 1 real zero that occurs 1 time.

<h3>How to determine the true statement</h3>

The function of f(x) is represented as:

$f(x)=x^3-2x^2+4x-8$

Differentiate the function f(x)

$f'(x)=3x^2-4x+4$

Calculate the minimum value using:

$x = -\frac b{2a}$

So, we have:

$x = -\frac {-4}{2*3}$

$x = \frac {2}{3}$

Substitute 2/3 in f'(x)

$f'(2/3)=3*(2/3)^2-4(2/3)+4$

$f'(2/3)=\frac 83$

The value of f'(2/3) is greater than 0.

This means that the function f(x) has 1 real zero, and it occurs once at point (2,0)

Hence, the true statement is (b)

what is the mean absolute deviation of the following numbers 18,28,24,25,15. ​

what is the mean absolute deviation of the following numbers 18,28,24,25,15.