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Virty [35]
3 years ago
12

A candle burns down at the rate of 0.5 inches per hour. The original height of the candle was 8 inches.

Mathematics
1 answer:
11111nata11111 [884]3 years ago
3 0

Answer: PART A.

y= remaining height of candle

x= rate the candle burns down in inches per hour

8= original height of candle

the function would be y=8- 0.5x because the candle starts at a height of 8 feet and loses half an inch per hour.

You can use this function to create ordered pairs by putting in number at x which indicates the time:

x=1

y=8- (.5×1)= 7.5

(1, 7.5)

you can then do this for other numbers and get:

(2, 7.0) (3, 6.5) (4, 6.0) (5, 5.5) (6, 5.0)

PART B.

This equation is a function because all of the x-values had different y-values as seen in the coordinates (1, 7.5) (2, 7.0) (3, 6.5) (4, 6.0) (5, 5.5) (6, 5.0)  

PART C.

If the rate was 0.4 inches an hour, it would still be a function because the rate is the only thing that changed making the new function y= 8- 0.4x.This equation would make coordinates of (0,8) (1, 7.6) (2, 7.2) (3, 6.8) and so on with each x value creating a different y value.

Step-by-step explanation: hope this helps

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babunello [35]

Answer:

It's A. segment A"B" is closer to segment C than segment A"B".

Step-by-step explanation:

5 0
3 years ago
A toaster has four slots for bread. Once the toaster is warmed up, it takes 35 seconds to make 4 slices of toast, 70 seconds to
soldier1979 [14.2K]

Answer:

192.5

Step-by-step explanation:

You are adding 35 sec to every 4 pieces of bread once you get to 20 you divide 35 and get 17.5 so the answer id 192.5

6 0
3 years ago
Identify the area of segment MNO to the nearest hundredth. HELP PLEASE!! I don't understand it!
katrin2010 [14]

Answer:

  13.98 in²

Step-by-step explanation:

I don't understand it, either.

Point N is part of a "segment" that above and to the right of chord MO. It is the sum of the areas of 3/4 of the circle and a right triangle with 7-inch sides. The larger segment MO to the upper right of chord MO has an area of about 139.95 in², which <u>is not</u> an answer choice.

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The remaining segment, to the lower left of chord MO does not seem to have anything to do with point N. However, its area is 13.98 in², which <u>is</u> an answer choice. Therefore, we think the question is about this segment, and we wonder why it is called MNO.

The area of a segment is given by the formula ...

  A = (1/2)(θ -sin(θ))r² . . . . . . where θ is the central angle in radians.

Here, we have θ = π/2, r = 7 in, so we can compute the area of the smaller segment MO as ...

  A = (1/2)(π/2 -sin(π/2))(7 in)² = 24.5(π/2 -1) in² ≈ 13.9845 in²

Rounded to hundredths, this is ...

  ≈ 13.98 in²

3 0
3 years ago
A sample of size 20 from a normal distribution has sample mean 3.5 and sample variance 14.75. Find 90% confidence intervals for
aleksley [76]

Answer:

Variance =9.2983, 27.6927

Standard deviation = 3.0493, 5.2624

Step-by-step explanation:

n = 20

S = 14.75

X² = chisquare

N-1 = degree of freedom

Alpha = 0.1

Alpha/2 = 0.1/2 = 0.05

1-0.1/2 = 0.95

Using statistics table

X² 19,0.05 = 30.14

X² 19, 0.95 = 10.12

A. 19(14.75)/30.14 , 19(14 75)/10.12

= 9.2983, 27.6927 for the variance of the population

B. Standard deviation = square root of variance

= √9.2983, √27.6927

= 3.0493, 5.2624

Please use attachment for better understanding

5 0
3 years ago
Find the​ fourth-degree polynomial function with zeros 4​, -4, 4i ​, and -4i . Write the function in factored form.
Iteru [2.4K]

Given:

A fourth-degree polynomial function has zeros 4​, -4, 4i ​, and -4i .

To find:

The fourth-degree polynomial  function in factored form.

Solution:

The factor for of nth degree polynomial is:

P(x)=(x-a_1)(x-a_2)...(x-a_n)

Where, a_1,a_2,...,a_n are n zeros of the polynomial.

It is given that a fourth-degree polynomial function has zeros 4​, -4, 4i ​, and -4i. So, the factor form of given polynomial is:

P(x)=(x-4)(x-(-4))(x-4i)(x-(-4i))

P(x)=(x-4)(x+4)(x-4i)(x+4i)

P(x)=(x-4)(x+4)(x^2-(4i)^2)           [\because a^2-b^2=(a-b)(a+b)]

On further simplification, we get

P(x)=(x-4)(x+4)(x^2-4^2i^2)

P(x)=(x-4)(x+4)(x^2+16)                [\because i^2=-1]

Therefore, the required fourth degree polynomial is P(x)=(x-4)(x+4)(x^2+16).

6 0
2 years ago
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