Given the equation 4(3b + 2)² = 64,
dividing both sides of the equation by 4, we have
(3b + 2)² = 16 and getting the square root of both sides,
(3b + 2) = 4 and (3b + 2) = -4
We can solve for b for each equation and have
3b = 2 | 3b = -6
b = 2/3 | b = -2
Therefore, the values of b are 2/3 and -2 and from the choices, the answer is <span>A: b = 2/3 and b = -2.</span>
Answer:
this is just math jargon... a conjugate is the same numbers but with an opposite sign.. got it?
Step-by-step explanation:
z1' ( the prime is often used for conjuates it's also used in calculus but later)
Z1' =8-i
7 = r^1/2 is the same as saying 7 = square root of r. So, to get rid of the square root sign on the r, you need to square it, and when you do something to one side of the equation, you have to do the same to the other side. So after squaring both sides, you get 49 = r.
Try to use photo math it gives you the work and answer
