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Citrus2011 [14]
3 years ago
11

Emma says that Function A has a greater initial value. Is Emma correct? Justify your response.

Mathematics
1 answer:
enot [183]3 years ago
4 0

Answer:

B. you can check the second one

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100PNTS! I desperately need help/answers to these please :(
kotykmax [81]

Answer:

1a- Alternate Exterior Angles

1b- Alternate Interior Angles

1c-Alternate Exterior Angles

1d-Alternate Interior Angles

1e-Alternate Exterior Angles

1f-Alternate Interior Angles

2a-None

2b-None

2c-Alternate Exterior Angles

2d-None

2e-Alternate Interior Angles

2f-None

2g-None

2h-None

2i-None

2j-None

6 0
3 years ago
If y varies directly as x, find the constant of variation if y = 25 and x = 5.
Soloha48 [4]

Answer:

The constant of variation is 5

Step-by-step explanation:

We know direct variation is of the form

y = kx

We know y =25 and x=5

25 = k*5

Divide each side by 5

25/5 = 5k/5

5 = k

3 0
3 years ago
I’ll mark youyou brainlist I’ll mark youyou brainlist
ale4655 [162]
8r + 206 + 7r +79 = 360
15r + 285 = 360
15r = 75
r = 5

7(5) + 79
35 + 79

angle YMB is 114°
3 0
3 years ago
Read 2 more answers
a pumpkin falls of a fence that is 3.0 m high (Accelerations due to gravity is 10 m/s *squared ) How fast does the pumpkin hit t
Rufina [12.5K]
3 seconds.

********************
3 0
3 years ago
The circumference of the equator of a sphere was measured to be 82 82 cm with a possible error of 0.5 0.5 cm. Use linear approxi
True [87]

Answer:

The maximum error in the calculated surface area is approximately 8.3083 square centimeters.

Step-by-step explanation:

The circumference (s), in centimeters, and the surface area (A_{s}), in square centimeters, of a sphere are represented by following formulas:

A_{s} = 4\pi\cdot r^{2} (1)

s = 2\pi\cdot r (2)

Where r is the radius of the sphere, in centimeters.

By applying (2) in (1), we derive this expression:

A_{s} = 4\pi\cdot \left(\frac{s}{2\pi} \right)^{2}

A_{s} = \frac{s^{2}}{\pi^{2}} (3)

By definition of Total Differential, which is equivalent to definition of Linear Approximation in this case, we determine an expression for the maximum error in the calculated surface area (\Delta A_{s}), in square centimeters:

\Delta A_{s} = \frac{\partial A_{s}}{\partial s} \cdot \Delta s

\Delta A_{s} = \frac{2\cdot s\cdot \Delta s}{\pi^{2}} (4)

Where:

s - Measure circumference, in centimeters.

\Delta s - Possible error in circumference, in centimeters.

If we know that s = 82\,cm and \Delta s = 0.5\,cm, then the maximum error is:

\Delta A_{s} \approx 8.3083\,cm^{2}

The maximum error in the calculated surface area is approximately 8.3083 square centimeters.

6 0
3 years ago
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