City planners are creating a 3-dimensional model of a city park to find the best placement for a new tennis court. The city park
is on a rectangular plot of land that is 1,500 ft long and 600 ft wide. The scale model of the park measures 7.5 ft x 3 ft. If the dimensions of the actual tennis court must be 120 ft long and 60 ft wide, what are the dimensions of the tennis court in the scale model?
First, divide the original measurements with the scaled ones. You'll get the same answer meaning that is the scale used by the model. 1500 ft. ÷7.5 ft = 200 600 ft. ÷ 3 ft. = 200
To simply check, if you divide 1500 with 200, the answer is 7.5 and 600 divided by 200 is 3. To find the scaled dimension of the tennis court with actual dimension of 120 ft by 60 ft, divide both values with the scale used in the model which is 200.
120 ft. ÷ 200 = 0.6 ft 60 ft. ÷ 200 = 0.3 ft
The dimension of the tennis court in the scaled model is 0.6 ft long and 0.3 ft. wide.
if one angle is 70º, and the other is 90º, that means that the first two angles equal 160º. since all three interior angles of a triangle have to add up to 180º, the third angle must be 20º.
