Question

Please solve the attached problem and chose from the answers below.

Answer 1

Answer:

C

Step-by-step explanation:

$\frac{5}{4t}-\frac{t+4}{10t^2}=\frac{5\left(10t^2\right)-4t\left(t+4\right)}{40t^3}=\frac{2t\left(25t-2\left(t+4\right)\right)}{40t^3}=\frac{\left(25t-2t-8\right)}{20t^2}=\frac{23t-8}{20t^2}$

Answer 2

For this case we must find the value of the following expression:

$\frac {5} {4t} - \frac {t + 4} {10t ^ 2}$

So, we have:

$\frac {5 * 10t ^ 2-4t (t + 4)} {4t * 10t ^ 2} =\\\frac {50t ^ 2-4t ^ 2-16t} {40t ^ 3} =$

We add similar terms:

$\frac {46t ^ 2-16t} {40t ^ 3} =$

We simplify dividing the numerator and denominator by 2:

$\frac {23t ^ 2-8t} {20t ^ 3} =$

We factor the numerator:

$\frac {t (23t-8)} {20t ^ 3} =$

We simplify:

$\frac {23t-8} {20t ^ 2}$

Answer:

Option C