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NARA [144]
3 years ago
14

(Please Help) Line s ‖ segment RP. m∠3 = m∠__?

Mathematics
1 answer:
goldfiish [28.3K]3 years ago
7 0
<span>before answering this question, we should know the properties of angles and parallel lines. For example, two angles are called interior alternate angles, if each angle is created by the existence of two parallel lines and a an another line called transversal. As for our case, 3 and 5 are alternate angles, so meas 3 = meas 5. It verifies Z test when we look at the figure.</span>
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70 POINTS SIMPLE QUESTION ...im just dumb PLEASE HELP...
gogolik [260]

Answer:

A dilation of 2 about the origin.

Step-by-step explanation:

You can see in the original figure the points are half the points of the transformed figure.

For example the coordinates of H are (0.5,0)

The coordinates of H' are (1,0)

Since 0.5 * 2 = 1

There is a dilation of 2 about the origin.

8 0
3 years ago
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Sauron [17]

Answer:

Area of ΔPQR is 28 units²

Step-by-step explanation:

-P is the point with coordinates ( 0, y-intercept for line x-2y+2 =0)

-rearrange the equation in the point-slope form y=mx+b  to find the y coordinate of the point P( 0, b)

x-2y+2 = 0, subtract x and 2 from both sides

-2y = -x-2, divide by -2 both sides

y= (1/2)x +1 so b=1 and P (0, 1)

-Q  is the point with coordinates ( 0, y-intercept for line 3x+y -15 =0)

-rearrange the equation in the point-slope form y=mx+b  to find the y coordinate of the point Q( 0, b)

3x +y -15 =0, subtract 3x and add 15 to both sides

y= -3x +15 so b=15 and Q(0,15)

-R is the intersection of the two lines so is the solution of the system of equations y= (1/2)x +1 and y= -3x +15

(1/2)x +1 =  -3x +15, add 3x and subtract1

(1/2) x+3x = 15-1, combine like terms

(7/2)x = 14 , multiply both sides by 2

7x = 28, divide both sides by 7

x= 4

y= (1/2)x +1 = (4/2) +1 =3 so R(4,3)

- the area of ΔPQR is (base *height)/2

base= 15-1= 14

height = 4

A= (14*4)/2 = 14*2 = 28

6 0
2 years ago
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lys-0071 [83]
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4 0
3 years ago
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Helen [10]

Answer:

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Step-by-step explanation:

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3 years ago
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