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aleksklad [387]
3 years ago
13

The distance from the normal hairline to the base of the nose is equal to to the distance from the base of the chin to the

Mathematics
1 answer:
inn [45]3 years ago
8 0

The answer is eyebrow. According to a research, the mean distance from chin to nose was 6.96 cm. The mean distance from nose to eyebrows was 6.55 cm. The mean space from eyebrows to hairline was 6.8 cm. while, the space from chin to hairline was 20.3 cm.

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(2b/3)^4 simplify the expression
Vladimir [108]

Answer:

\large\boxed{\left(\dfrac{2b}{3}\right)^4=\dfrac{16b^4}{81}}

Step-by-step explanation:

\left(\dfrac{2b}{3}\right)^4\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\ \text{and}\ (ab)^n=a^nb^n\\\\=\dfrac{2^4b^4}{3^4}=\dfrac{16b^4}{81}

6 0
3 years ago
3 feet of ribbons are needed for wrapping each present. How many presents can be wrapped with 102cm of ribbons?
bagirrra123 [75]

1 imperial foot has approximately 30.48 metric centimeters, and for one present we need 3 ft, or namely 3(30.48) cm, how many can we get from 102 cm?   102 ÷ 3(30.48) ≈ 1.1155, so barely just one present.

8 0
3 years ago
Read 2 more answers
Separate non-x terms from x terms
wel

Answer:X^2-7X=57/4

Step-by-step explanation:

Y=X^2-7X+57/4

X^2-7X=57/4

6 0
3 years ago
In the regular nonagon shown, what is the measure of angle x?<br>A.36<br>B.40<br>C.45<br>D.60
Rudik [331]
The answer is 45 i took the test i got it correct
6 0
3 years ago
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What is question 32 and can you please explain how to do it.
lukranit [14]

Answer is B.

5√3(5+2√6)=

25√3+10√18=

25√3+30√2

Note: I multiplied 10 by 3, because the prime factors of 18 are 3, 3 and 2 so I made a pair from the 3 and multipled and was left with 2.


5 0
3 years ago
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