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3 years ago

If the mean of this data is 95, find the missing data 103,99,90,86,105,96 what is the missing data

1 answer:

3 0

Let, the missing number = x
Then, 103 + 99 + 90 + 86 + 105 + 96 + x / 7 = 95
579+x = 665
x = 665 - 579
x = 86

In short, Your Answer would be 86

Hope this helps!

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Consider the following hypothesis test:

KengaRu [80]

Answer:

(a) $t= -1.540$

(b) $0.10 < p < 0.20$

Step-by-step explanation:

Given

$H_o: =18$ $H_a: \ne 18$

$n = 48$

$\bar x = 17$

$\sigma = 4.5$

Solving (a): The test statistic

This is calculated as:

$t= \frac{\bar x - \mu_o}{\sigma/\sqrt n}$

So, we have:

$t= \frac{17 - 18}{4.5/\sqrt{48}}$

$t= \frac{- 1}{4.5/6.93}$

$t= \frac{- 1}{0.6493}$

$t= -1.540$ --- approximated

Solving (b): Range of p value

First, calculate the degree of freedom (df)

$df = n - 1$

$df = 48 - 1$

$df = 47$

Using:

$\alpha = 0.05$ --- significance level

The p value at: $df = 47$ is:

$p = 0.065133$

and the range is:

$0.05 * 2 < p < 2 * 0.10$

$0.10 < p < 0.20$

Solving (c): The conclusion

Compare the p value to the level of significance value

We have:

$p = 0.065133$

$\alpha = 0.05$

By comparison:

$p > \alpha$

because:

$0.065133 > 0.05$

Hence, the conclusion is: fail to reject $H_o$

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3 years ago

Is the square root of 23 rational or irrational

skelet666 [1.2K]

It is irrational because it’s not terminating (please hit “thanks”

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Answer:

$\huge \boxed{-11}$

Step-by-step explanation:

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$-(3+8)$

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What is the rate of change for y= 8/7x + 5

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A psychology professor assigns letter grades on a test according to the following scheme. A: Top 7% of scores B: Scores below th

NISA [10]

Answer:

The minimum score required for an A grade is 89.8.

Step-by-step explanation:

We are given that a psychology professor assigns letter grades on a test according to the following scheme. A : Top 7% of scores. B : Scores below the top 7% and above the bottom 64%. C : Scores below the top 36% and above the bottom 25%. D : Scores below the top 75% and above the bottom 6%. F : Bottom 6% of scores.

Scores on the test are normally distributed with a mean of 78.4 and a standard deviation of 7.6.

Let X = Scores on the test

SO, X ~ Normal( $\mu=78.4,\sigma^{2} =7.6^{2}$ )

The z-score probability distribution for normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = mean time = 78.4

$\sigma$ = standard deviation = 7.6

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, the minimum score required for an A grade so that it represents Top 7% of scores is given by;

P(X $\geq$ x) = 0.07 {where x is the required minimum score