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3 years ago

Prove that angles formed by the noncongruent sides of a kite are congruent (Hint: Draw a diagonal of the kite. )

1 answer:

3 0

Well,It depends on the shape of the kite and to decide that something is congruent is it has to be the exact same shape looks same everything same YW :D

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Nia answered 80% of the 40 questions on a test correctly. How many correct answers did she have?

Step2247 [10]

Nia answered correct answers = 80% of the 40 questions

When we remove % sign from a number, we divide that number by 100

= $\frac{80}{100}$ of 40

= $\frac{80}{100} \times 40$

Cancelling the two zeroes from numerator and denominator,

= $8 \times 4$

= 32.

Total correct answers answered by Nia = 32

3 0

3 years ago

Read 2 more answers

A line through the origin and (10,4) is showin in the standard (x,y) coordinate plane below. The acute angle between the line an

Snowcat [4.5K]

Answer:

$\cos\theta=\frac{10}{\sqrt{116}}$

Step-by-step explanation:

To solve this, we can imagine a line drawn directly down from the point (10,4) to the x-axis. This would make a right triangle with length 10 and height 4.

$\cos\theta$ is equal to the length of adjacent leg to the angle divided by the length of the hypotenuse of the triangle. From the picture, we can see the adjacent leg is 10.

We can use Pythagorean's Theorem to find the hypotenuse (let $c$ represent the length of the hypotenuse):

$10^2+4^2=c^2$

$100+16=c^2$

$116=c^2$

$c=\sqrt{116}$

Thus, we know the adjacent is 10, and the hypotenuse is $\sqrt{116}$ . This means $\cos\theta=\frac{10}{\sqrt{116}}$ .

Hope this helps!

5 0

2 years ago

What is the y intercept of y=5x+1

finlep [7]

The y intercept is (0, 1)

4 0

2 years ago

Type the correct answer in each box. If necessary, round your answers to the nearest hundredth.

disa [49]

Answer:

Perimeter = 32.44 units

Area = 30 square units

Step-by-step explanation:

Given

Vertices

A(2,8), B(16,2) and C(6,2)

WE have to determine the lengths of all sides before finding the perimeter and area.

The formula of modulus is:

$d = \sqrt{(x_{2}- x_{1})^{2} +(y_{2}-y_{1})^{2}}\\AB=\sqrt{(16-2)^{2} +(2-8)^{2}}\\=\sqrt{(14)^{2} +(-6)^{2}}\\=\sqrt{196+36}\\ =\sqrt{232}\\=15.23\\\\BC=\sqrt{(6-16)^{2} +(2-2)^{2}}\\=\sqrt{(-10)^{2} +(0)^{2}}\\=\sqrt{100+0}\\ =\sqrt{100}\\=10\\\\AC=\sqrt{(6-2)^{2} +(2-8)^{2}}\\=\sqrt{(4)^{2} +(-6)^{2}}\\=\sqrt{16+36}\\ =\sqrt{52}\\=7.21\\\\$

So the perimeter is:

$Perimeter=AB+BC+AC\\=15.23+10+7.21\\=32.44\ units$

Using hero's formula,

$s=\frac{perimeter}{2}\\s=\frac{32.44}{2}\\ s=16.22\\Area=\sqrt{s(s-a)(s-b)(s-c)}\\=\sqrt{16.22(16.22-15.23)(16.22-10)(16.22-7.21)}\\=\sqrt{(16.22)(0.99)(6.22)(9.01)}\\=\sqrt{899.91}\\=29.99\ square\ units$

Rounding off will give us 30 square units ..

4 0

3 years ago

X^ 3 +x^ 2 +4x/x^ 2 +x-2<br>into partial<br>fractions

lawyer [7]

Answer:

x + (4/ x-2) + (2/ x-1)

Step-by-step explanation:

x + (6x/ x^2 + 2x - x -2)

x + (6x/ (x + 2) X (x - 1))

(6x/ (x + 2) X (x - 1))

(A/ x+2) + (B/ x-1)

(6x/ (x + 2) X (x - 1)) = (A/ x+2) + (B/ x-1)

6x = Ax + Bx - A + 2B

6x = (A+B)x + (-A+2b)

{0 = -A+2B

{6 = A+B

(A,B) = (4, 2)

(4/ x+2) + (2/ x-1)

x + (4/ x-2) + (2/ x-1)

6 0

3 years ago