The equation of a line is 3x + 8y - 16 = 0.
1 answer:
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Let's say if both work together, they can do it in "t" hrs
so, if Latoya can do it by herself in 14hrs, how much can she do in 1hr? well, she can do only 1/14 of the total
if Lisa can do it in 10hrs by herself, how much can she do in 1hr? well, 1/10 of the total
now, let's add their rate together, keeping in mind, their rate added, will be doing in 1hr only 1/t of the total work
thus
so, they'd do it in 5hrs and 5/6 of an hour, which is just 50mins, so, 5hrs and 50mins
so, if Latoya can do it by herself in 14hrs, how much can she do in 1hr? well, she can do only 1/14 of the total
if Lisa can do it in 10hrs by herself, how much can she do in 1hr? well, 1/10 of the total
now, let's add their rate together, keeping in mind, their rate added, will be doing in 1hr only 1/t of the total work
thus
so, they'd do it in 5hrs and 5/6 of an hour, which is just 50mins, so, 5hrs and 50mins
A. It's a composite function, so basically, wherever you see a p, replace it with 5t, because we are given that information. So, your answer is:
![A[p(t)] = 5t \pi 2=10t \pi](https://tex.z-dn.net/?f=A%5Bp%28t%29%5D%20%3D%205t%20%5Cpi%202%3D10t%20%5Cpi%20)
B. Let's use the function we created, and just plug in 2 for t:
![A[p(2)] = 10(2) \pi](https://tex.z-dn.net/?f=A%5Bp%282%29%5D%20%20%3D%2010%282%29%20%5Cpi%20)
![A[p(2)] = 62.83](https://tex.z-dn.net/?f=A%5Bp%282%29%5D%20%3D%2062.83)
So, your answer is (approximately) 62.83 units².
B. Let's use the function we created, and just plug in 2 for t:
So, your answer is (approximately) 62.83 units².