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ludmilkaskok [199]
3 years ago
6

What equation can equal 66 but also equal 25

Mathematics
1 answer:
Ainat [17]3 years ago
8 0

Equations have two sides which equal each other.  The equation itself doesn't really equal anything.

Perhaps the question is what equation has solutions (also known as roots) equal to 66 and 25?

There are infinitely many, including

(x-66)(x-25)=0

That's an equation, so we can just call it done.  But let's expand because we can:

(x-66)(x-25)=x² - 91x + 1650

Answer: x² - 91x + 1650 = 0

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Answer:

this is the answer

Step-by-step explanation:

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Write the equation in vertex form of the parabola with the vertex (-4,-4) that goes through the point (-2,-16)
Brrunno [24]

Answer:

- 3(x + 4) {}^{2}  - 4

Step-by-step explanation:

Vertex form is

a(x - h) {}^{2}  + k = f(x)

We know that h and k are both -4. Let x be -2 and y be -16.

a( - 2  + 4) {}^{2}   - 4 =  - 16

a(2) {}^{2}  - 4 =  - 16

4a - 4 =  - 16

4a =  - 12

a =  - 3

So the equation in vertex form is

- 3(x  + 4) {}^{2}  - 4

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What is the product ? (9t-4)(-9t-4)
solmaris [256]
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What is the answer please.... need help
mina [271]

Answer:

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

f\left(x\right)=x^3-6x^2+3x+10

As the highest power of the x-variable is 3 with the leading coefficients of 1.

  • So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

f\left(x\right)=x^3-6x^2+3x+10

0=x^3-6x^2+3x+10              ∵  f(x)=0

as

Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0

so

\left(x+1\right)\left(x-2\right)\left(x-5\right)=0    

Using the zero factor principle

if  ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x=-1,\:x=2,\:x=5

Therefore, the zeros of the function are:

x=-1,\:x=2,\:x=5

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.    

8 0
3 years ago
Can someone help me please
UNO [17]

The interior angles are 3, 4, and 6. Angle 3 is adjacent to angle 1, so is not remote.

The remote interior angles to angle 1 are

... A. angle 4

... E. angle 6

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