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vichka [17]
3 years ago
11

Find the roots of the function f(x)=x2+6x

Mathematics
2 answers:
MakcuM [25]3 years ago
4 0

Answer:

-6 & 0

Step-by-step explanation:

x² + 6x = 0

x(x + 6) = 0

x = 0 or x + 6 = 0

x = 0, x = -6

Inga [223]3 years ago
3 0

Answer:

The roots are 0, -6

Step-by-step explanation:

f(x)=x^2+6x

Set the function equal to zero to find the roots

0 = x^2 +6x

Factor an x

0 = x(x+6)

Using the zero product property, set each term equal to zero

x=0   x+6 =0

x=0  x = -6

The roots are 0, -6

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6 0
3 years ago
Find the angle measures. Justify your responses.
MatroZZZ [7]

Answer:

m∠3 = 2x - 10° and m∠6 = 3x + 20

m∠3 = 58°          ;    m ∠6 = 122°

Step-by-step explanation:

a ║ b

m∠2 = m∠6                     If ║ cut by a transversal, then corresponding angles

                                         are ≅ and =

m∠7 = m∠3                   If ║ cut by a transversal, then corresponding angles

                                       are ≅ and =

m∠2 = 3x + 20              Given

m∠7 = 2x - 10                 Given    

m∠6 + m∠3 = 180°         If ║ cut by a transversal, then each pair of same-side

                                       interior angles (also called consecutive interior angles

                                       are supplementary (sum = 180°) .    

3x + 20 + 2x - 10 = 180°

5x + 10 = 180°

5x = 170°

x = 34°

Answer:   m∠3 = 2x - 10° and m∠6 = 3x + 20

                m∠3 = 2(34) - 10  ;    m∠6 = 3(34) + 20

                 m∠3 = 58°          ;    m ∠6 = 122°

                                 

5 0
2 years ago
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