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777dan777 [17]
3 years ago
11

A city determines that a planned community must have at least 4 acres of developed and open space, and the difference between th

e number of developed acres, y, and the number of open acres, x, can be no more than 1. Which graph represents the system of inequalities for this scenario? x + y ≤ 4 y – x ≥ 1

Mathematics
2 answers:
stepan [7]3 years ago
5 0

Answer:

Option B.

Step-by-step explanation:

Let x be the number of open acres and y be the number of developed acres.

It is given that a community must have at least 4 acres of developed and open space.

x+y\geq 4

The difference between the number of developed acres, y, and the number of open acres, x, can be no more than 1.

y-x\leq 1

The relative equations of both inequalities are

x+y=4

y-x=1

The table of values

For line 1                      For line 2

x      y                            x      y

0     4                            0      1

4     0                           -1      0

Plot these ordered pairs on a coordinate plane and draw both lines.

The related line of first inequality is a solid line and shaded area lies above the line because the sign of inequality is ≥.

The related line of second inequality is a solid line and shaded area lies below the line because the sign of inequality is ≤.

Therefore, the correct option is B.

Bezzdna [24]3 years ago
3 0

Answer:

The graph in the attached figure

Step-by-step explanation:

Let

x ----> the number of open acres

y ----> the number of developed acres

we know that

x+y \geq 4 -----> inequality A

The solution of the inequality A is the shaded area above the solid line x+y=4

y-x\leq 1 -----> inequality B

The solution of the inequality B is the shaded area below the solid line y-x=1

so

The graph in the attached figure

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