Since the big triangle is an isosceles one, we conclude that the angles of the left triangle are: 32, 90 and 3x-10. Sinche the sum of this angles have to be 180° we have:

$(3x-10)+32+90=180$

Solving for x, we have:

$\begin{gathered} (3x-10)+32+90=180 \\ 3x-10+32+90=180 \\ 3x=180+10-90-32 \\ 3x=68 \\ x=\frac{68}{3} \\ x=22.67 \end{gathered}$

Therefore, x=22.67 and the answer is A.

7 0

1 year ago

Find the axis of symmetry for this parabola: <br><br> y=-5x^2-10x-13

Dmitry [639]

Answer:

x=1

Step-by-step explanation:

1. Complete the square on the right side of the equation.

5 ( x − 1 )2 − 18

2. Use the vertex form, y = a ( x − h ) 2 + k , to determine the values of a , h , and k . a= 5 h = 1 k = − 18

3. Since the value of a is positive, the parabola opens up.

Opens Up

4. Find the vertex ( h , k ) . ( 1 , − 18 )

5. Find p , the distance from the vertex to the focus.

1 /20

6. Find the focus.

7. ( 1 , − 359/ 20 )

8. Find the axis of symmetry by finding the line that passes through the vertex and the focus.

ANSWER: x = 1

6 0

3 years ago

Help!!!! Plssss!!! ASAP

zimovet [89]

Answer:

The y-intercept is (0,-26)

Step-by-step explanation:

Given two points P(a,b) and Q(c,d), the line that passes for both points can be found with the expression

$\displaystyle y-b=\frac{d-b}{c-a}(x-a)$

We'll take the first two points P(34,-52) and Q(51,-65) to find

$y=-\frac{13}{17}(x-34)-52\\ \\y=-\frac{13}{17}x-26$

Let's verify if the third point is on the line:

$y=-\frac{13}{17}68-26=-52-26=-78$

It belongs to the line. To find the y-intercept of the line, we set x to 0

$y=-\frac{13}{17}(0)-26=-26$

The y-intercept is (0,-26)

5 0

3 years ago