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3 years ago

Simplify 5(x - 2) + 3x A.8x - 2 B.8x - 10 C.-7x

Mathematics

2 answers:

timofeeve [1]3 years ago

7 0

The answer should be B. 8x-10

Novosadov [1.4K]3 years ago

5 0

The answer is B because u multiply each number in parenthesis by 5

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3 years ago

Explain how 6/12 and 4/8 are equal fractions

bogdanovich [222]

6/12 and 4/8 are equal fractions, as, when simplified, they share a simplified fraction.

Note that what you do to the denominator, you do to the numerator. Find common denominators for both fractions:

(4/8)/(2/2) = 2/4

(6/12)/(3/3) = 2/4

As you can tell, when they share a common denominator (4), the numerators are the same as well (3).

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3 years ago

A cheetah run 70 miles per hour what is the speed for feet per hour

pochemuha

Answer:

The correct answer to this question is that the cheetah can run 369,000 feet per hour. We can work this out in the following way:

One mile equals 1760 yards

In feet that is 3 x 1760 or 5,280

So Feet per hour will be 5280 x 70 or

369,600 feet per hour.

Read more on Brainly.com - brainly.com/question/134707#readmore

Step-by-step explanation:

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3 years ago

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Komok [63]

Answer:

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Step-by-step explanation:

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2 years ago

If cos() = − 2 3 and is in Quadrant III, find tan() cot() + csc(). Incorrect: Your answer is incorrect.

nydimaria [60]

Answer:

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}$

Step-by-step explanation:

Given

$\cos(\theta) = -\frac{2}{3}$

$\theta \to$ Quadrant III

Required

Determine $\tan(\theta) \cdot \cot(\theta) + \csc(\theta)$

We have:

$\cos(\theta) = -\frac{2}{3}$

We know that:

$\sin^2(\theta) + \cos^2(\theta) = 1$

This gives:

$\sin^2(\theta) + (-\frac{2}{3})^2 = 1$

$\sin^2(\theta) + (\frac{4}{9}) = 1$

Collect like terms

$\sin^2(\theta) = 1 - \frac{4}{9}$

Take LCM and solve

$\sin^2(\theta) = \frac{9 -4}{9}$

$\sin^2(\theta) = \frac{5}{9}$

Take the square roots of both sides

$\sin(\theta) = \±\frac{\sqrt 5}{3}$

Sin is negative in quadrant III. So:

$\sin(\theta) = -\frac{\sqrt 5}{3}$

Calculate $\csc(\theta)$

$\csc(\theta) = \frac{1}{\sin(\theta)}$

We have: $\sin(\theta) = -\frac{\sqrt 5}{3}$

So:

$\csc(\theta) = \frac{1}{-\frac{\sqrt 5}{3}}$

$\csc(\theta) = \frac{-3}{\sqrt 5}$

Rationalize

$\csc(\theta) = \frac{-3}{\sqrt 5}*\frac{\sqrt 5}{\sqrt 5}$

$\csc(\theta) = \frac{-3\sqrt 5}{5}$

So, we have:

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta)$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \tan(\theta) \cdot \frac{1}{\tan(\theta)} + \csc(\theta)$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 + \csc(\theta)$

Substitute: $\csc(\theta) = \frac{-3\sqrt 5}{5}$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 -\frac{3\sqrt 5}{5}$

Take LCM

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}$

6 0

3 years ago