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3 years ago

11

2 planes left a airport at noon 1 flew east and the other flew west as twice the speed after 3 hours the planes were 2700 miles

apart. How fast was each plane flying?

2 answers:

zvonat [6]3 years ago

7 0

X=speed of the first plane. (east)
2x=speed of the second plane (west).

we can suggest this equation:
3(x+2x)=2700
3(3x)=2700
9x=2700
x=2700/9
x=300

speed of the first plane=300 miles/h
speed of the second plane=2x=2(300 miles/h)=600 miles/h.

Answer: the speed of the first plane was 300 miles/h, and the speed of the second plane was 600 miles/h.

const2013 [10]3 years ago

5 0

Speed =distance ÷time
?=2700÷3
?=900 miles per hour

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Answer:

The solutions of the system of equations are the points

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Step-by-step explanation:

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