2 planes left a airport at noon 1 flew east and the other flew west as twice the speed after 3 hours the planes were 2700 miles
apart. How fast was each plane flying?
2 answers:
X=speed of the first plane. (east)
2x=speed of the second plane (west).
we can suggest this equation:
3(x+2x)=2700
3(3x)=2700
9x=2700
x=2700/9
x=300
speed of the first plane=300 miles/h
speed of the second plane=2x=2(300 miles/h)=600 miles/h.
Answer: the speed of the first plane was 300 miles/h, and the speed of the second plane was 600 miles/h.
Speed =distance ÷time
?=2700÷3
?=900 miles per hour
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