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andrew11 [14]
3 years ago
11

How do I solve this equation 144=-12(x+5)

Mathematics
1 answer:
Papessa [141]3 years ago
6 0
First you distribute the -12 to the (x+5) getting 144=-12x-60.

Next you add 60 to each side getting 204=-12x

Then you divide each side by -12 getting -17=x, which is the answer.<span />
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A trail mix recipe calls for pound of peanuts, pound of raisins, and pound of
tester [92]

Answer:

Peanuts to Raisins!

Step-by-step explanation:

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3 years ago
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If 4 peanut butter cups cost $0.96 and the peanut butter cups all cost the same amount, what is the price of each peanut butter
Oksanka [162]
We can set up an equation with x as the price of one cup:
4x=0.96
x=0.96/4=0.24

Each cup is $0.24

Hope this helped!
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3 years ago
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Consider random samples of size 58 drawn from population A with proportion 0.77 and random samples of size 70 drawn from populat
fredd [130]

Answer:

Step-by-step explanation:

a) The formula for determining the standard error of the distribution of differences in sample proportions is expressed as

Standard error = √{(p1 - p2)/[(p1(1 - p1)/n1) + p2(1 - p2)/n2}

where

p1 = sample proportion of population 1

p2 = sample proportion of population 2

n1 = number of samples in population 1,

n2 = number of samples in population 2,

From the information given

p1 = 0.77

1 - p1 = 1 - 0.77 = 0.23

n1 = 58

p2 = 0.67

1 - p2 = 1 - 0.67 = 0.33

n2 = 70

Standard error = √{(0.77 - 0.67)/[(0.77)(0.23)/58) + (0.67)(0.33)/70}

= √0.1/(0.0031 + 0.0032)

= √1/0.0063

= 12.6

the standard error of the distribution of differences in sample proportions is 12.6

b) the sample sizes are large enough for the Central Limit Theorem to apply because it is greater than 30

8 0
3 years ago
Quiz
Tasya [4]

Answer:

1603

Step-by-step explanation:

3^3*4^3-5^3

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3*3*3=9*3=27

4*4*4=16*4=64

5*5*5=25*5=125

(27*64)-125

1728-125

1603

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In which quadrant or on which axis do each of the points (-2,4) , (3,-1) ,(-1,0), (1,2) and
exis [7]

Answer:

Step-by-step explanation:

cartesian plane :

quadrant 1 : both x and y are positive

quadrant 2 : x is negative, y is positive

quadrant 3 : both x and y are negative

quadrant 4 : x is positive and y is negative

(-2,4)......we have x is negative and y is positive...so we are in quadrant 2

(3,-1)....we have x is positive and y is negative...in quadrant 4

(-1,0) ...if u have a 0 in ur points, they do not lie in any quadrant because they are located on an axis....this is located on axis x

(1,2)....both are positive....located in quadrant 1

(-3,-5)...both are negative.....quadrant 3

5 0
3 years ago
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