Answer:
P(F | C) = 0.96
Step-by-step explanation:
Hi!
This is a problem on conditional probability. Lets call:
C = { cloudy day }
F = { foggy day }
Then F ∩ C = { cloudy and foggy day }
You are asked for P(F | C), the probability of a day being foggy given it is cloudy. By definition:

And the data you have is:

Then: P(F | C) = 0.96
Answer:
if x=-1 then its is NOT in the domain of h.
Step-by-step explanation:
Domain is the set of values for which the function is defined.
we are given the function
h(x) = x + 1 / x^2 + 2x + 1
h(x) = x+1 /x^2+x+x+1
h(x) = x+1/x(x+1)+1(x+1)
h(x) = x+1/(x+1)(x+1)
h(x) = x+1/(x+1)^2
So, the function h(x) is defined when x ≠ -1
Its is not defined when x=-1
So, if x=-1 then its is NOT in the domain of h.
Hey there! :)
Answer:
0.3.
Step-by-step explanation:
Looking at the row for "Less than 80° F", the column for "Rain" shows a 0.3 probability in the table. Therefore:
The probability of rain on a day less than 80°F is 0.3.
Answer: (x−3)(x+7)
=(x+−3)(x+7)
=(x)(x)+(x)(7)+(−3)(x)+(−3)(7)
=x^2+7x−3x−21
=x^2+4x−21