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Firdavs [7]
3 years ago
12

Find all values of x that are NOT in the domain of h.

Mathematics
2 answers:
tankabanditka [31]3 years ago
7 0

Answer: x=-1

Step-by-step explanation:

Given the function h(x):

h(x)=\frac{x+1}{ x^2 + 2x + 1}

The values that are not in the domain of this function are those values that  make the denominator equal to zero.

Then, to find them, you can make the denominator equal to zero and solve for "x":

x^2 + 2x + 1=0\\\\(x+1)(x+1)=0\\\\(x+1)^2=0\\\\x=-1

Firlakuza [10]3 years ago
4 0

Answer:

if x=-1 then its is NOT in the domain of h.

Step-by-step explanation:

Domain is the set of values for which the function is defined.

we are given the function

h(x) = x + 1 / x^2 + 2x + 1

h(x) = x+1 /x^2+x+x+1

h(x) = x+1/x(x+1)+1(x+1)

h(x) = x+1/(x+1)(x+1)

h(x) = x+1/(x+1)^2

So, the function h(x) is defined when x ≠ -1

Its is not defined when x=-1

So, if x=-1 then its is NOT in the domain of h.

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Answer:

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4 0
2 years ago
What Val are restricted from the domain of
djverab [1.8K]

<u>Given</u>:

The given expression is \frac{\left(4 x^{2}-4 x+1\right)}{(2 x-1)^{2}}

We need to determine the values for which the domain is restricted.

<u>Restricted values:</u>

Let us determine the values restricted from the domain.

To determine the restricted values from the domain, let us set the denominator the function not equal to zero.

Thus, we have;

(2x-1)^2\neq 0

Taking square root on both sides, we get;

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Thus, the restricted value from the domain is x\neq \frac{1}{2}

Hence, Option A is the correct answer.

7 0
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