Answer: 
Move all terms containing y to the left, all other terms to the right
<u>Add -14y to each side of the equation</u>
<u></u>
<u></u>
<u></u>
<u>Combine like terms: 5y + -14y = -9y
</u>
<u></u>
<u></u>
<u></u>
<u>Combine like terms: 14y + -14y = 0
</u>
<u></u>
<u></u>
<u></u>
<u>Add '20' to each side of the equation</u>
<u></u>
<u></u>
<u></u>
<u>Combine like terms: -20 + 20 = 0
</u>
<u></u>
<u></u>
<u></u>
<u>Combine like terms: 7 + 20 = 27
</u>
<u></u>
<u></u>
<u></u>
<u>Divide each side by -9</u>
<u></u>
<u></u>
1/6
explanation:
1 x 1 = 1
2 x 3 = 6
1/6
Hope it helps!
Applying the inscribed angle theorem, the measure of arc AB that doesn't go through point C is: 100 degrees.
<h3>What is the Inscribed Angle Theorem?</h3>
Based on the inscribed angle theorem, if ∅ is the inscribed angle measure, the measure of the central angle subtended by the same arc equals 2(∅).
m∠BAC = 40 degrees.
Central angle = 2(40) = 80 degrees [based on the inscribed angle theorem]
Corresponding arc BC = 80 degrees.
Arc AC through point B = 180 degrees [half circle]
Arc AB = 180 - arc BC = 180 - 80 = 100 degrees.
Learn more about the inscribed angle theorem on:
brainly.com/question/3538263
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I don’t know what the formula stands for but if it was in years instead of months I could totally answer

We want to find
such that
. This means



Integrating both sides of the latter equation with respect to
tells us

and differentiating with respect to
gives

Integrating both sides with respect to
gives

Then

and differentiating both sides with respect to
gives

So the scalar potential function is

By the fundamental theorem of calculus, the work done by
along any path depends only on the endpoints of that path. In particular, the work done over the line segment (call it
) in part (a) is

and
does the same amount of work over both of the other paths.
In part (b), I don't know what is meant by "df/dt for F"...
In part (c), you're asked to find the work over the 2 parts (call them
and
) of the given path. Using the fundamental theorem makes this trivial:

