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Aleksandr-060686 [28]
3 years ago
15

" title="{x}^{ log_{3}(x) } = 81 {x}^{3} " alt="{x}^{ log_{3}(x) } = 81 {x}^{3} " align="absmiddle" class="latex-formula">
can you solve by algebraically, not graphing and provide step by step explanation, please?​
Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
3 0

Answer:

x=81 or 1/3

Step-by-step explanation:

x^\log_3(x)} =81x^3\\\log_3(x^{\log_3(x)})=\log_3(81x^3)\\\(\log_3x)(\log_3x)=\log_381+\log_3x^3\\(\log_3x)^2=3\log_3x^+4\\\\Let u=\log_3x\\\\u^2-3u-4=0\\(u-4)(u+1)=0\\u=4 \\4=\log_3x\\x=3^4=81\\\\u=-1\\-1=\log_3x\\x=3^{-1}=1/3

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1/3^-1-1^-1/4^-1<br>find the value in the following equation ​
nadezda [96]

Answer:

-1/6

Step-by-step explanation:

= 1/3 (-1-1) x -1/4 (-1)

= 1/3 (-2) x 1/4

= -2/3 x 1/4

= -2\12

2 and 12 can cancel out each other.

so the answer will be.

= -1/6.

4 0
3 years ago
Which function has zeros at x = 10 and x = 2? f(x) = x2 – 12x + 20 f(x) = x2 – 20x + 12 f(x) = 5x2 + 40x + 60 f(x) = 5x2 + 60x +
4vir4ik [10]
To find the correct function, just plug in 10 and 2 to see if the function equals zero with both numbers.

f(x)=x^2-12x+20
f(10)=100-120+20
f(10)=0         --> that's what we want, so let's check the other number

f(x)=x^2-12x+20
f(2)=4-24+20
f(2)=0          --> perfect. this function has zeros at both x=10 and x=2

The function that has zeros at both x=10 and x=2 is f(x)=x^2-12x+20.
5 0
3 years ago
Read 2 more answers
PLEASE HELP URGENT MY MOM WILL GROUND ME IF I DONT FINISH THIS LOL
exis [7]

Step-by-step explanation:

Hope it helps you in your learning process.

8 0
3 years ago
If: f(x) = 2.50x + 15; then: f(6) = show work
SSSSS [86.1K]
2.5(6) + 15
= 15 + 15
=30
7 0
3 years ago
Round to the nearest ten and hundred 829
Musya8 [376]
To the nearest ten, 829 would become <em><u>830</u></em> because the ones digit (9) is closer to 30 than it is to 20. So we would round up.

To round to the nearest hundred, we look at the tens and ones digit. 29 is less than 50 so we would have to round down to <em><u>800</u></em> instead of rounding up to 900.

Hope that helps :)
4 0
3 years ago
Read 2 more answers
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