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Aleksandr-060686 [28]
3 years ago
15

" title="{x}^{ log_{3}(x) } = 81 {x}^{3} " alt="{x}^{ log_{3}(x) } = 81 {x}^{3} " align="absmiddle" class="latex-formula">
can you solve by algebraically, not graphing and provide step by step explanation, please?​
Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
3 0

Answer:

x=81 or 1/3

Step-by-step explanation:

x^\log_3(x)} =81x^3\\\log_3(x^{\log_3(x)})=\log_3(81x^3)\\\(\log_3x)(\log_3x)=\log_381+\log_3x^3\\(\log_3x)^2=3\log_3x^+4\\\\Let u=\log_3x\\\\u^2-3u-4=0\\(u-4)(u+1)=0\\u=4 \\4=\log_3x\\x=3^4=81\\\\u=-1\\-1=\log_3x\\x=3^{-1}=1/3

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timama [110]

Answer:

8√13 units

Step-by-step explanation:

We use the distance formula.

The distance formula states that the distance between two points (x, y) and (a, b) is equal to:

d = \sqrt{(x-a)^2+(y-b)^2}

Here, x = 6, y = -1, a = -18, and b = 15. Plug these in:

d = \sqrt{(x-a)^2+(y-b)^2}

d = \sqrt{(6-(-18))^2+(-1-15)^2}=\sqrt{24^2+(-16)^2} =\sqrt{576 + 256} =\sqrt{832} = 8√13

The answer is thus 8√13 units.

<em>~ an aesthetics lover</em>

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3 years ago
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