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Aleksandr-060686 [28]
3 years ago
15

" title="{x}^{ log_{3}(x) } = 81 {x}^{3} " alt="{x}^{ log_{3}(x) } = 81 {x}^{3} " align="absmiddle" class="latex-formula">
can you solve by algebraically, not graphing and provide step by step explanation, please?​
Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
3 0

Answer:

x=81 or 1/3

Step-by-step explanation:

x^\log_3(x)} =81x^3\\\log_3(x^{\log_3(x)})=\log_3(81x^3)\\\(\log_3x)(\log_3x)=\log_381+\log_3x^3\\(\log_3x)^2=3\log_3x^+4\\\\Let u=\log_3x\\\\u^2-3u-4=0\\(u-4)(u+1)=0\\u=4 \\4=\log_3x\\x=3^4=81\\\\u=-1\\-1=\log_3x\\x=3^{-1}=1/3

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Jlenok [28]

Answer:

Luis would need to have a SAT score of 574.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Nicole's z-score:

ACT scores have a mean of about 21 with a standard deviation of about 5, which means that \mu = 21, \sigma = 5

Nicole gets a score of 24, which means that X = 24. Her z-score is:

Z = \frac{X - \mu}{\sigma}

Z = \frac{24 - 21}{5}

Z = 0.6

What score would Luis have to have on the SAT to have the same standardized score(z-score) as Nicole's standardized score on the ACT?

Luis would have to get a score with a z-score of 0.6, that is, X when Z = 0.6.

SAT scores have a mean of about 508 with a standard deviation of about 110, which means that \mu = 508, \sigma = 110.

The score is:

Z = \frac{X - \mu}{\sigma}

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X - 508 = 0.6*110

X = 574

Luis would need to have a SAT score of 574.

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3 years ago
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