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2 years ago

Square root of 19 is between what two decimal numbers to the nearest tenth

Mathematics

2 answers:

Ludmilka [50]2 years ago

8 0

It’s in between 4.3 and 4.4

mojhsa [17]2 years ago

6 0

Answer:

4 and 5

Step-by-step explanation:

4.35 is in between 4 and 5

stan ateez

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Which ratio is less than<br>7/15<br>o

Gemiola [76]

2/5=6/15 and that is less than 7/15

3 0

2 years ago

can I please get a labeled homework help im confused and last thing please don't make to much long equation because I cant do so

zepelin [54]

Answer:

your answer is x >18

Step-by-step explanation:

Jahsiah's mistake was he added 9 to both sides of the equation. He should have subtracted 9 from both sides of the equation.

Here's the solution

-2x+9<-27

-9 -9

-2x/-2x<-36/-2x

when u divide by negative in inequalities, u change the sign. So ur correct answer is x>18

hope this helped.

6 0

2 years ago

Add.

Dovator [93]

Answer:

6x²+4x

Step-by-step explanation:

The given expressions are 3x²- 4x-4 and 3x²+8x+4.

We need to add these two expressions.

3x²- 4x-4 + 3x²+8x+4 = 3x² + 3x² -4x+8x-4+4

= 6x²+4x

On adding the given expressions, we get the value as 6x²+4x. Hence, the sum of the given expressions is equal to 6x²+4x

4 0

2 years ago

A 3x4x5 rectangular cuboid (e.g. a brick) is painted blue and cut into 1x1 cubes. what is the expected value for the painted sid

Anton [14]

Answer:

8 cubes are painted on 3 sides

24 cubes are painted on 2 sides

22 cubes are painted on 1 sides

6 cubes are painted on 0 side

E = 3 * 8/60 + 2 * 24/60 + 1 * 22/60 + 0 * 6/60 = 47/30 = 1.567

4 0

3 years ago

3^x= 3*2^x solve this equation

kompoz [17]

In the equation

$3^x = 3\cdot 2^x$

divide both sides by $2^x$ to get

$\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3$

Take the base-3/2 logarithm of both sides:

$\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}$

Alternatively, you can divide both sides by $3^x$ :

$\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13$

Then take the base-2/3 logarith of both sides to get

$\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}$

(Both answers are equivalent)

8 0

2 years ago