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Burka [1]
3 years ago
10

The midpoint of AB is at (3,7) and A is at (0,-5). Where is B located?

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
3 0
\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ \square }}\quad ,&{{ \square }})\quad 
%  (c,d)
&({{ \square }}\quad ,&{{ \square }})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)\qquad thus
\\
----------------------------\\\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
A&({{ 0}}\quad ,&{{ -5}})\quad 
%  (c,d)
B&({{ \square }}\quad ,&{{ \square }})
\end{array}\qquad
%   coordinates of midpoint 
(3,7)\impliedby midpoint\qquad thus
\\ \quad \\
\left(\cfrac{{{ x_2 }} + {{ 0}}}{2}=3\quad ,\quad \cfrac{{{ y_2 }} + {{( -5)}}}{2}=7 \right)\to 
\begin{cases}
\cfrac{{{ x_2 }} + {{ 0}}}{2}=3
\\ \quad \\
\cfrac{{{ y_2 }} + {{ -5}}}{2}=7
\end{cases}
\\ \quad \\
solve\ for\ x_2\ and\ y_2
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2 trains leave the station at the same time. Train A is traveling 16 miles slower than train B. The two trains are 720 miles apa
Ber [7]

Answer: the rate of speed for train A is 66 miles per hour.

Step-by-step explanation:

Let x represent the speed of train B.

2 trains leave the station at the same time. Train A is traveling 16 miles per hour slower than train B. This means that the speed of train A would be x - 16 miles per hour.

The two trains are 720 miles apart after 4 hours. It means that both trains traveled a total distance of 720 miles in 4 hours.

Distance = speed × time

Distance travelled by train A after 4 hours is

4(x - 16) = 4x - 64

Distance travelled by train B after 4 hours is

4 × x = 4x

Since the total distance travelled by both trains is 720 miles, then

4x - 64 + 4x = 720

8x = 720 - 64 = 656

x = 656/8 = 82 miles per hour

The speed of train A would be

82 - 16 = 66 miles per hour.

6 0
3 years ago
20 POINTS AND BRAINLIEST !! PLEASE ANSWER THIS QUESTION !!
Elenna [48]
A
(X-7)(x-4) -> x^2 -11x + 28
Multiply that by the 2 and you get the original equation!
5 0
3 years ago
What is. 500 plus 500??<br><br> Help!!
san4es73 [151]
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7 0
2 years ago
Read 2 more answers
The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 60 o
krok68 [10]

Answer:

a) 99.7% of the widget weights lie between 45 and 75 ounces

b) 97.2% of the widget weights lie between 50 and 75 ounces

c) 84% of the widget weights lie above 55

Step-by-step explanation:

The Empirical Rule states that:

50% of the values of a measure is above the mean, and the other 50% is below the mean.

99.7% of the values of a measure lie between 3 standard deviations of the mean.

95% of the values of a measure lie between 2 standard deviations of the mean.

68% of the values of a measure lie between 1 standard deviations of the mean.

In this problem, we have that: The widget weights have a mean of 60 ounces and a standard deviation of 5 ounces.

(a) 99.7% of the widget weights lie between

3 standard deviations of the mean, so:

60 - 3*5 = 60 + 3*5 = 45 and 75 ounces

(b) What percentage of the widget weights lie between 50 and 75 ounces?

We have to find the percentage that are below 75 and subtract by the percentage that are below 50. So

75 is 3 standard deviations above the mean. So 99.7% of the measures are below 75.

50 is 2 standard deviations below the mean. So only 5% of the measures that are below the mean are below 50.

So

99.7% - (50%)5% = 99.7% - 2.5% = 97.2%

(c) What percentage of the widget weights lie above 55?

55 is one standard deviation below the mean.

50% of the widget weights are above the mean.

Of the 50% that is below, 68% lie between one standard deviation(So from 55 to 60)

So

50% + 68%(50%) = 84%

3 0
3 years ago
For what value of a does<br> (9) ***<br> = 3438-1<br> -1<br> 0<br> 1<br> no solution
mario62 [17]

Answer:

<h2>0</h2>

solution,

(\frac{1}{7} ) ^{3a + 3}  =  {343}^{a - 1}  \\ or \: ( {7}^{ - 1} ) ^{3a + 3}  =  {(7}^{3} ) ^{a - 1}  \\ or \: (7) ^{ - 3a - 3}  =  {(7)}^{3a - 3}  \\ or \:  - 3a - 3 = 3a - 33 \\ or \:  - 3a - 3a =  - 3 + 3 \\ or \:  - 6a =  0 \\  \: a = 0

hope this helps..

Good luck on your assignment..

3 0
3 years ago
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